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Usersdbo
USWarbo
 

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    1. CO@peterwkc Haskell uses spaces to separate function names from their arguments (eg. "foo x y") unlike many other languages which use brackets and commas (eg. "foo(x, y)"). Here, "f" is a function with one argument. That argument is a list of characters (a string). We can use recursion as long as the string is getting shorter. "f []" is the non-recursive base case, "f ('\n':' ':a)" recurses on "('\n':a)" which is one char shorter, "f (a:b)" recurses on "b" which is one char shorter. "x:y:z" is the syntax for a list.
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    2. COTo clarify: `list($x) = foo();` is equivalent to `$x = foo()[0];`. Note that this is not necessarily the same as "get the first item", since even an integer-indexed array may not have an element with key 0. In my case I was doing "list($order) = get_order($user);" but "get_order" was returning orders keyed by their ID, which was usually not 0. As @Sergiy says, array_values() fixes this, but detracts from the efficiency and (more importantly) readability of the code.
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    3. CO@AlixAxel You're right that multi-dimensional != bi-dimensional, but this can be composed to flatten any number of levels. One nice consequence of composing folds is that it obeys a fixed limit; if I have an array nested to 5 levels, I can `fold` it into 4 levels, or `fold . fold` it to get 3 levels, or `fold . fold . fold` it to get 2 levels, etc. This also prevents bugs getting hidden; eg. if I want to flatten a 5D array but I'm given a 4D array, the error will trigger immediately.
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