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  1. USautistic
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    <p><strong>Sebastian Ivor Ramadan. Not here. <a href="https://www.socialmediatoday.com/social-networks/how-spot-narcissist-social-media" rel="nofollow noreferrer">Here</a> and <a href="https://www.reddit.com/search?q=stackoverflow" rel="nofollow noreferrer">here</a>. Good luck. I'm outties!</strong></p> <p><strong>autism <code>/ˈɔːtɪz(ə)m/</code></strong> <em>noun</em>. a mental condition, present from early childhood, characterized by great difficulty in communicating and forming relationships with other people and in using language and abstract concepts.</p> <p><strong>StackOverflow is discriminating (illegally)</strong>. From an ethical standpoint, if you won't allow people to refer themselves as <em>"mentally retarded"</em> (as I choose to identify) then you shouldn't allow people to refer to themselves using <em>any</em> of the encompassed or equivalent terminologies. <em>Mentally ill</em>, <em>handicapped</em>, they're all equivalent, and if one isn't permitted, none should be... hence, StackOverflow is engaging in <em>discrimination</em> by <em>censoring peoples pseudonyms</em>.</p> <p><strong>I want my pseudonym back</strong>, which I am legally entitled to, according to the <a href="https://creativecommons.org/licenses/by-sa/3.0/au/legalcode" rel="nofollow noreferrer">CC-BY-SA 3.0 license</a> which must be enforced (rather than violated) by community moderation:</p> <blockquote> <p>When You Distribute or publicly perform the Work or any Derivative Work or Collection <strong>You must provide</strong>, in a manner reasonable to the medium or means You are using:</p> <ul> <li><strong>the name or pseudonym (if provided)</strong> of the Original Author and/or of any other party (such as a sponsor institute, publishing entity or journal) <strong>that the Original Author or Licensor has requested be attributed</strong> (such as in the copyright notice or terms of use). In this clause 4C these parties are referred to as "Attribution Parties";</li> </ul> </blockquote> <p><strong>StackOverflow has violated their license</strong> with all of us by violating this condition of licensing. All licenses with creators on StackOverflow are hereby legally <em>void</em> according to the <em>termination</em> section of the license:</p> <blockquote> <p>This Licence and the rights granted to You under this Licence shall terminate automatically upon any breach by You of the terms of the Licence.</p> </blockquote>
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