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    <p>For starters, you will need to be using an instance of <code>SortedMap</code>. If the map doesn't implement that interface, then it has an undefined/arbitrary iteration order and you can't control it. (Generally this is the case, since a map is a way of associating values with keys; ordering is an auxiliary concern.)</p> <p>So I'll assume you're using <a href="http://docs.oracle.com/javase/6/docs/api/java/util/TreeMap.html" rel="nofollow">TreeMap</a>, which is the canonical sorted map implementation. This sorts its keys according to a <a href="http://docs.oracle.com/javase/6/docs/api/java/util/Comparator.html" rel="nofollow">Comparator</a> which you can supply in the constructor. So if you can write such a comparator that determines which is the "lower" of two arbitrary keys (spoiler alert: you can), this will be straightforward to implement.</p> <p>This will, however, only work when sorting by key. I don't know if it makes much sense to sort a map by value, and I'm not aware of any straightforward way to do this. The best I can think of is to write a <code>Comparator&lt;Map.Entry&gt;</code> that sorts on values, call <code>Map.getEntrySet</code> and push all the entries into a list, then call <code>Collections.sort</code> on the list. It's not very elegant or efficient but it should get the job done if performance isn't your primary concern.</p> <p>(Note also that if your keys aren't immutable, you will run into a lot of trouble, as they won't be resorted when externally changed.</p>
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