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    <p>MySQL is flexible in <code>SELECT</code> list subqueries, so you can do something like the following, without even needing a <code>FROM</code> clause on the main query.</p> <pre><code>SELECT (SELECT SUM(costres) - SUM(costadmin) FROM call_history, client WHERE MONTH(start) = 3 AND YEAR(start) = 2012 AND call_history.client_reseller_id = client.id AND client.charging_identifier &lt;&gt; 100000 AND client.charging_identifier &lt;&gt; 999999 ) + ( SELECT SUM(costcl) - SUM(costadmin) FROM call_history, client WHERE MONTH(start) = 3 AND YEAR(start) = 2012 AND call_history.client_reseller_id = client.id AND client.charging_identifier = 100000 AND client.charging_identifier &lt;&gt; 999999 ) AS yourSum; </code></pre> <p>I can't remember if MySQL permits <code>UNION</code> inside subqueries. If it does, it is a little nicer to use <code>SUM()</code> them across a <code>UNION</code>:</p> <pre><code>SELECT SUM(total) as grand_total FROM ( SELECT SUM(costres) - SUM(costadmin) AS total FROM call_history, client WHERE MONTH(start) = 3 AND YEAR(start) = 2012 AND call_history.client_reseller_id = client.id AND client.charging_identifier &lt;&gt; 100000 AND client.charging_identifier &lt;&gt; 999999 UNION ALL SELECT SUM(costcl) - SUM(costadmin) AS total FROM call_history, client WHERE MONTH(start) = 3 AND YEAR(start) = 2012 AND call_history.client_reseller_id = client.id AND client.charging_identifier = 100000 AND client.charging_identifier &lt;&gt; 999999 ) unionsub </code></pre> <h3>Update:</h3> <p>A quick test tells me that you can use <code>UNION ALL</code> in a subquery, at least in MySQL 5.6.</p>
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    1. POAdding totals from two unrelated MySQL queries
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    1. USMichael Berkowski
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    1. COWhoa that was quick! Thanks both. So simple, I knew it would be. Will test and report back.
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    2. COMichael, your second query works fine - the first also does but as you said its a little less elegant.
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    3. CO@btongeorge Great, happy to help.
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