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POStomp Broadcast with Rabbitmq and Python
 

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    <p>Im trying to move a system from using morbid to rabbitmq, but I cannot seem to get the same broadcast behaviour morbid supplied by default. By broadcast I mean that when a message is added to the queue, every consumer recieves it. With rabbit, when a message is added they are distributed round robin style to every listener.</p> <p>Can anyone tell me how to achieve the same kind of message distribution?</p> <p>The stomp library used below is <a href="http://code.google.com/p/stomppy/" rel="nofollow noreferrer">http://code.google.com/p/stomppy/</a></p> <p>Failing being able to do with with stomp, even a amqplib example would really help.</p> <p>My code at present looks like this</p> <p>The Consumer</p> <pre><code>import stomp class MyListener(object): def on_error(self, headers, message): print 'recieved an error %s' % message def on_message(self, headers, message): print 'recieved a message %s' % message conn = stomp.Connection([('0.0.0.0', 61613), ('127.0.0.1', 61613)], 'user', 'password') conn.set_listener('', MyListener()) conn.start() conn.connect(username="user", password="password") headers = {} conn.subscribe(destination='/topic/demoqueue', ack='auto') while True: pass conn.disconnect() </code></pre> <p>And the sender looks like this</p> <pre><code>import stomp class MyListener(object): def on_error(self, headers, message): print 'recieved an error %s' % message def on_message(self, headers, message): print 'recieved a message %s' % message conn = stomp.Connection([('0.0.0.0', 61613), ('127.0.0.1', 61613)], 'user', 'password') conn.set_listener('', MyListener()) conn.start() conn.connect(username="user", password="password") headers = {} conn.subscribe(destination='/topic/demotopic', ack='auto') while True: pass conn.disconnect() </code></pre>
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      1. USPhillip Whelan
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