StackOverflow2013

Note that there are some explanatory texts on larger screens.

plurals

POIntersection between two Arcs? (arc = distance between pair of angles)
primarykey
Id
9800829
data
AcceptedAnswerId
9803826
AnswerCount
2
ClosedDate
CommentCount
5
CommunityOwnedDate
CreationDate
2012-03-21T08:16:09.003
FavoriteCount
1
LastActivityDate
2015-03-22T21:23:47.950
LastEditDate
2015-03-22T21:23:47.950
LastEditorUserId
1118321
OwnerUserId
887512
ParentId
0
PostTypeId
1
Score
2
ViewCount
3000
LastEditorDisplayName
text
Body
I'm trying to find a way to calculate the intersection between two arcs. I need to use this to determine how much of an Arc is visually on the right half of a circle, and how much on the left. I though about creating an arc of the right half, and intersect that with the actual arc. But it takes me wayyy to much time to solve this, so I thought about asking here - someone must have done it before. Edit: I'm sorry the previous illustration was provided when my head was too heavy after crunching angles. I'll try to explain again: In <a href="http://i.stack.imgur.com/QSu2D.png" rel="nofollow">this link</a> you can see that I cut the arc in the middle to two halves, the right part of the Arc contains 135 degrees, and the left part has 90. This Arc starts at -180 and ends at 45. (or starts at 180 and ends at 405 if normalized). I have managed to create this code in order to calculate the amount of arc degrees contained in the right part, and in the left part: <pre><code>f1 = (angle2>270.0f?270.0f:angle2) - (angle1<90.0f?90.0f:angle1); if (f1 < 0.0f) f1 = 0.0f; f2 = (angle2>640.0f?640.0f:angle2) - (angle1<450.0f?450.0f:angle1); if (f2 < 0.0f) f2 = 0.0f; f3 = (angle2>90.0f?90.0f:angle2) - angle1; if (f3<0.0f) f3=0.0f; f4 = (angle2>450.0f?450.0f:angle2) - (angle1<270.0f?270.0f:angle1); if (f4<0.0f) f4=0.0f; </code></pre> It works great after normalizing the angles to be non-negative, but starting below 360 of course. Then f1 + f2 gives me the sum of the left half, and f3 + f4 gives me the sum of the right half. It also does not consider a case when the arc is defined as more than 360, which may be an "error" case. BUT, this seems like more of a "workaround", and not a correct mathematical solution. I'm looking for a more elegant solution, which should be based on "intersection" between two arc (because math has no "sides", its not visual"; Thanks!!
Tags
<math><geometry><trigonometry><angle>
Title
Intersection between two Arcs? (arc = distance between pair of angles)
singulars
PostAcceptedAnswerId
1. PO
 singulars
 PostTypePostTypeId
 PTAnswer
PostParentId
1. This table or related slice is empty.
PostTypePostTypeId
1. PTQuestion
UserLastEditorUserId
1. USuser1118321
UserOwnerUserId
1. USdaniel.gindi
plurals
PostLinksPostIdRelatedPostId
1. This table or related slice is empty.
PostLinksRelatedPostIdPostId
1. PL
 singulars
 LinkTypeLinkTypeId
 LTLinked
PostsAcceptedAnswerId
1. This table or related slice is empty.
PostsParentIdCreationDate
1. PO
 singulars
 PostTypePostTypeId
 PTAnswer
VotesPostIdCreationDate
1. VO
 singulars
 PostPostId
 POIntersection between two Arcs? (arc = distance between pair of angles)
 UserUserId
 This table or related slice is empty.
 VoteTypeVoteTypeId
 VTDownMod
2. VO
 singulars
 PostPostId
 POIntersection between two Arcs? (arc = distance between pair of angles)
 UserUserId
 This table or related slice is empty.
 VoteTypeVoteTypeId
 VTUpMod
CommentsPostId

Querying!

Guidance

A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.