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    <p>I would propose to use 2 joins</p> <pre><code>SELECT * FROM photo JOIN photo_selectedTags as photo_selectedTags6 -- this join restricts to 'photo.COUNTER' whic have TAGS_COUNTER = 6 ON photo.COUNTER = photo_selectedTags6.PHOTO_COUNTER AND photo_selectedTags6.TAGS_COUNTER = 6 JOIN photo_selectedTags as photo_selectedTags192 -- this join restricts to 'photo.COUNTER' whic have TAGS_COUNTER = 192 ON photo.COUNTER = photo_selectedTags192.PHOTO_COUNTER AND photo_selectedTags192.TAGS_COUNTER = 192 </code></pre> <p><br/><br/> Also would be possible to achive it with analytical functions (if supported by your DB)</p> <pre><code>-- This one works on teradata. Something similar should work on oracle. Don't know about others SELECT * FROM photo LEFT JOIN photo_selectedTags ON photo.COUNTER = photo_selectedTags.PHOTO_COUNTER QUALIFY max(case when photo_selectedTags.TAGS_COUNTER = 6 then 1 end) over (partition by photo.COUNTER) = 1 AND max(case when photo_selectedTags.TAGS_COUNTER = 192 then 1 end) over (partition by photo.COUNTER) = 1 </code></pre> <p>If you have many values in the list (in addition to 192,6), then this might be possible solution</p> <pre><code>SELECT * FROM photo JOIN ( SELECT PHOTO_COUNTER, count(distinct TAGS_COUNTER) cnt FROM photo_selectedTags WHERE TAGS_COUNTER in (192,6) HAVING cnt = 2 -- adjust this according to the number of different values ) as pht ON photo.COUNTER = pht.PHOTO_COUNTER </code></pre> <p>In subquery only PHOTO_COUNTERs are left which have both (192 and 6), then this is joined</p>
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    1. POIN Clause selects all variables
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    1. COThank you! The first example works, the second has in issue with the QUALIFY line. Is there a way to combine these into one join or does it have to be separated out? I'd imagine this could blog down if I'm looking for more than 2 tags.
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      1. USJesse Clark
 

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