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POJava Reading Undecoded URL from Servlet
 

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  1. POJava Reading Undecoded URL from Servlet
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    <p>Let's presume that I have string like '=&amp;?/;#+%' to be a part of my URL, let's say like this:</p> <pre><code>example.com/servletPath/someOtherPath/myString/something.html?a=b&amp;c=d#asdf </code></pre> <p>where myString is the above string. I've encoded critical part so URL looks like</p> <pre><code>example.com/servletPath/someOtherPath/%3D%26%3F%2F%3B%23%2B%25/something.html?a=b&amp;c=d#asdf </code></pre> <p>So far so good. </p> <p>When I'm in the servlet and I read any of <code>request.getRequestURI()</code>, <code>request.getRequestURL()</code> or <code>request.getPathInfo()</code>, returned value is already decoded, so I get strilng like</p> <pre><code>someOtherPath/=&amp;?/;#+%/something.html?a=b&amp;c=d#asdf </code></pre> <p>and I can't differentiate between real special characters and encoded ones. </p> <p>I've solved particular problem by banning above chars altogether, which works in this situation, but I still wonder is there any way to get undecoded URL in servlet class.</p> <p>YET ANOTHER EDIT: When I've hit this problem last evening I was too tired to notice what is really going on, which is <em>even more bizarre!</em> I have servlet mapped on, say /servletPath/* after that I can put whatever I want and get my servlet responding depending on the rest of a path, <strong>except</strong> when there is %2F in the path. In that case <em>request never hits the servlet</em>, and I get 404! If i put '/' instead of %2F it works OK. I'm running Tomcat 6.0.14 on Java 1.6.0-04 on Linux.</p>
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    1. COif the string is already decoded, why would it have a %2f in it?
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      1. USMike Pone
    2. COWhat does the returned value look like and what do you want it to be? And is it relevant? I can't really tell what the problem is.
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      1. USMichael Myers
    3. COI don't get it.
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      1. USOscarRyz
 

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