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    <p>If I understand correctly the requirement is:</p> <pre><code>If the number is 3n, divide it in 3 groups of n, n and n elements. If the number is 3n+1, divide it in 3 groups of n+1, n and n elements. If the number is 3n+2, divide it in 3 groups of n+1, n+1 and n elements. </code></pre> <p>Best thing to do is to make that explicit in your code, and avoid any "clever" logic. The straight-forward splitting boils down to:</p> <pre><code>If the number is 3n, the divisions are: 0 .. n-1 n .. 2n-1 2n .. 3n-1 If the number is 3n+1, the divisions are: 0 .. n n+1 .. 2n 2n+1 .. 3n If the number is 3n+2, the divisions are: 0 .. n n+1 .. 2n+1 2n+2 .. 3n+1 </code></pre> <p>In c# that would be something like:</p> <pre><code>public static List&lt;int&gt; Divide3Columns(int total, int column) { int startIndex = 0; int endIndex = 0; int pageSize = total / 3; if (total % 3 == 0) { startIndex = column * pageSize; endIndex = (column + 1) * pageSize - 1; } if (total % 3 == 1) { if (column == 0) { startIndex = 0; endIndex = pageSize; //pageSize + 1 elements; } else { startIndex = column * pageSize + 1; endIndex = (column + 1) * pageSize; } } if (total % 3 == 2) { if (column == 2) { startIndex = 2 * pageSize + 2; endIndex = 3 * pageSize + 1; //same as total - 1; } else { startIndex = column * (pageSize + 1); endIndex = (column + 1) * pageSize + column; } } List&lt;int&gt; result = new List&lt;int&gt;(); for (int i = startIndex; i &lt;= endIndex; i++) { result.Add(i); } return result; } </code></pre> <hr> <p>The answer assumes that we will always <a href="http://en.wikipedia.org/wiki/Holy_Hand_Grenade" rel="nofollow">divide in 3, and only 3 columns</a>. If the number is variable, the logic to determine the columns can be generalized.</p>
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    1. PODivide by 3, function in C#
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    1. COit doesn't work
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    2. CO@ihorko fixed it, and added a more complete example
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