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    <p>javascript on page: </p> <pre><code>function submitPostForm(url, data) { var form = document.createElement("form"); form.action = url; form.method = 'POST'; form.style.display = 'none'; //if (typeof data === 'object') {} for (var attr in data) { var param = document.createElement("input"); param.name = attr; param.value = data[attr]; param.type = 'hidden'; form.appendChild(param); } document.body.appendChild(form); form.submit(); } </code></pre> <p>after some event (like a click on "submit"):</p> <pre><code>// products is now filled with a json array var products = jQuery('#spreadSheetWidget').spreadsheet('getProducts'); var postData = { 'action': action, 'products': products } submitPostForm(jQuery('#submitURLcreateorder').val(), postData); </code></pre> <p>in the controller:</p> <pre><code> /** * @Route("/varelager/bestilling", name="_varelager_bestilling") * @Template() */ public function bestillingAction(Request $request) { $products = $request-&gt;request-&gt;get('products', null); // json-string $action = $request-&gt;request-&gt;get('action', null); return $this-&gt;render( 'VarelagerBundle:Varelager:bestilling.html.twig', array( 'postAction' =&gt; $action, 'products' =&gt; $products ) ); } </code></pre> <p>in the template (bestilling.html.twig in my case):</p> <pre><code> {% block resources %} {{ parent() }} &lt;script type="text/javascript"&gt; jQuery(function(){ //jQuery('#placeDateWidget').placedate(); {% autoescape false %} {% if products %} jQuery('#spreadSheetWidget').spreadsheet({ enable_listitem_amount: 1, products: {{products}} }); jQuery('#spreadSheetWidget').spreadsheet('sumQuantities'); {% endif %} {% endautoescape %} }); &lt;/script&gt; {% endblock %} </code></pre> <p>Alrite, I think that's what you wanted :)</p> <p><strong>EDIT</strong> To send something without simulating a form you can use jQuery.ajax(). Here is an example in the same spirit as above which will not trigger a page refresh.</p> <pre><code>jQuery.ajax({ url: jQuery('#submitURLsaveorder').val(), data: postData, success: function(returnedData, textStatus, jqXHR ){ jQuery('#spreadSheetWidget').spreadsheet('clear'); window.alert("Bestillingen ble lagret"); // consume returnedData here }, error: jQuery.varelager.ajaxError, // a method dataType: 'text', type: 'POST' }); </code></pre>
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    1. POPosting JSON objects to Symfony 2
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    1. USЯрослав Рахматуллин
    1. USЯрослав Рахматуллин
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    1. COThanks for the speedy response! Essentially you are still submitting a normal form with javascript, that is kind of what i'm doing at the moment, I was wondering whether it was possible to directly post the JSON object without simulating a form, if not no drama. Also, once I have the JSON object in Symfony, is it possible to send it off to another service as a Request object?
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      1. USgreg
    2. COI addressed your comment in my edit. I'm not quite sure how to do ajax stuff without jQuery, so ill leave that to you. To send someone to another controller you can redirect them there. This is covered in http://symfony.com/doc/2.0/book/controller.html under *Redirecting* and *Forwarding*. Good luck!
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      1. USЯрослав Рахматуллин
    3. COThank you again, I should have been a little clearer, I can submit the object no problems, I just can't work out how to retrieve it in the controller without it having a name
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      1. USgreg
 

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