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    <p>The below is a helpful utility method for retrieving all subscribed event handlers for any routed event:</p> <pre><code>/// &lt;summary&gt; /// Gets the list of routed event handlers subscribed to the specified routed event. /// &lt;/summary&gt; /// &lt;param name="element"&gt;The UI element on which the event is defined.&lt;/param&gt; /// &lt;param name="routedEvent"&gt;The routed event for which to retrieve the event handlers.&lt;/param&gt; /// &lt;returns&gt;The list of subscribed routed event handlers.&lt;/returns&gt; public static RoutedEventHandlerInfo[] GetRoutedEventHandlers(UIElement element, RoutedEvent routedEvent) { // Get the EventHandlersStore instance which holds event handlers for the specified element. // The EventHandlersStore class is declared as internal. var eventHandlersStoreProperty = typeof(UIElement).GetProperty( "EventHandlersStore", BindingFlags.Instance | BindingFlags.NonPublic); object eventHandlersStore = eventHandlersStoreProperty.GetValue(element, null); // Invoke the GetRoutedEventHandlers method on the EventHandlersStore instance // for getting an array of the subscribed event handlers. var getRoutedEventHandlers = eventHandlersStore.GetType().GetMethod( "GetRoutedEventHandlers", BindingFlags.Instance | BindingFlags.Public | BindingFlags.NonPublic); var routedEventHandlers = (RoutedEventHandlerInfo[])getRoutedEventHandlers.Invoke( eventHandlersStore, new object[] { routedEvent }); return routedEventHandlers; } </code></pre> <p>Using the above, the implementation of your method becomes quite simple:</p> <pre><code>private void RemoveClickEvent(Button b) { var routedEventHandlers = GetRoutedEventHandlers(b, ButtonBase.ClickEvent); foreach (var routedEventHandler in routedEventHandlers) b.Click -= (RoutedEventHandler)routedEventHandler.Handler; } </code></pre>
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    1. POHow to remove all Click event handlers?
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    1. COThis is a very useful answer that is unfortunately attached to a closed question. I think the "duplicate" would be improved by you providing the same answer there as well.
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    2. CO@phloopy: Good suggestion. I just posted an [improved version](http://stackoverflow.com/a/12618521/1149773) of the above solution there.
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