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2012-02-24T17:24:43.573
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The neo4jrestclient supports both indexing and traversing the graph, but I think by using just indexing could be enoguh for your use case. However, I don't know if I understood properly your problem. Anyway, something like this could work: <pre><code>>>> from neo4jrestclient.client import GraphDatabase >>> gdb = GraphDatabase("http://localhost:7474/db/data/") >>> idx = gdb.nodes.indexes.create("urltags") >>> url_node = gdb.nodes.create(url="http://foo.bar", type="URL") >>> tag_node = gdb.nodes.create(tag="foobar", type="TAG") </code></pre> We add the property <code>count</code> to the relationship to keep track the number of URLs <code>"http://foo.bar"</code> tagged with the tag <code>foobar</code>. <pre><code>>>> url_node.relationships.create(tag_node["tag"], tag_node, count=1) </code></pre> And after that, we index the url node according the value of the URL. <pre><code>>>> idx["url"][url_node["url"]] = url_node </code></pre> Then, when I need to create a new URL node tagged with a TAG node, we first query the index to check if that is yet indexed. Otherwise, we create the node and index it. <pre><code>>>> new_url = "http://foo.bar2" >>> nodes = idx["url"][new_url] >>> if len(nodes): ... rel = nodes[0].relationships.all(types=[tag_node["tag"]])[0] ... rel["count"] += 1 ... else: ... new_url_node = gdb.nodes.create(url=new_url, type="URL") ... new_url_node.relationships.create(tag_node["tag"], tag_node, count=1) ... idx["url"][new_url_node["url"]] = new_url_node </code></pre>
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1. POIndexing nodes in neo4j in python
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1. COThanks a lot for your help..
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2. COYou're welcome :-D
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