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    <p>Try this:</p> <p><del>Important use <strong>mysql_real_escape_string</strong> on all USER INPUT, or you could hacked very easily</del> SEE comment from Dan Kanze. But its better to learn the MYSQLI extension Prepared Statements, its easier cleaner and securer Here a example. <a href="http://mattbango.com/notebook/web-development/prepared-statements-in-php-and-mysqli/" rel="nofollow">http://mattbango.com/notebook/web-development/prepared-statements-in-php-and-mysqli/</a></p> <p>Also this code is not very secure, cause a user can set $_GET['is_logged_in'] !== "1" manuell, you should maybe add a cookie to the user pc, with a unique value, that the user is logged in and that value matches his user/pass pair, which you store in your DB..</p> <p>Just google secure login form php or something like that.</p> <pre><code> &lt;?php require "dbconn.php"; if(@$_GET['showerror'] == "1"){ echo "Your login has failed. Try again"; exit; } if(!empty($_POST['username']){ $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $sql = "SELECT * FROM person WHERE name ='".$username."' AND password='".$password."'"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_array( $result ); if(!empty($row)){ $_SESSION['username'] = $row['name']; header("Location: index.html?is_logged_in=1?"; exit(); }else{ header("Location: index.html?showerror=1"); exit(); } } if(@$_GET['is_logged_in'] !== "1"){ // DISPLAY FORM }else{ // DO YOUR STUFF } ?&gt; </code></pre>
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    1. POPHP and HTML - Hiding a <form> when a user is logged in
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    1. COmysql_real_escape_string is depricated and can be used for blind sql injection attacks. do not use this.
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    2. COoh, i dont use it anymore, only prepared statements, i edit my answer. Thanks for letting know.
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