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    <p>Is your sample size bigger than 1 byte? If so then ...</p> <p>on ARM it is important to keep data aligned, so if you allocate BYTE (one byte) buffer and later cast it to SHORT (two bytes), then if BYTE buffer was allocated on odd address then you will get unaligned data access.</p> <p>So if your sample size is two bytes then you must ensure that your BYTE buffer address is always even. </p> <p>To verify this you can check what value does lpData have when error appears, if it is odd then simply allocate 1 byte more and send buffer+1 to winapi function.</p> <hr> <p>below is sample code with proper alignment, found at: <a href="http://www.utdallas.edu/~nsg051000/AmbientNoise4/Wave.cs" rel="nofollow">http://www.utdallas.edu/~nsg051000/AmbientNoise4/Wave.cs</a></p> <pre><code> /// /// Read a data buffer from the supplied BinaryReader. This method will /// allocate memory for the data buffer it is not already allocated. /// /// BinaryReader containing data /// Size, in bytes, to be read /// MMSYSERR.NOERROR if successful public MMSYSERR Read(BinaryReader rdr, uint readLength, int align) { uint bufferLength = readLength; if (bufferLength % align != 0) bufferLength += (uint)(align - (bufferLength % align)); dwBufferLength = bufferLength; byte[] data = new byte[readLength]; rdr.Read(data, 0, data.Length); if (lpData == IntPtr.Zero) lpData = Memory.LocalAlloc(Memory.LMEM_FIXED, (uint)bufferLength); if (lpData == IntPtr.Zero) return MMSYSERR.NOMEM; Marshal.Copy(data, 0, lpData, data.Length); return MMSYSERR.NOERROR; } </code></pre>
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    1. COI have tried the code with Waves with four byte blocks and two byte blocks, but all my lpData so far has been an even value and divisible by the appropriate block number. Is an IntPtr the actual memory address when working in C#?
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    2. COI dont do much c# programming, I have found sample code: http://www.utdallas.edu/~nsg051000/AmbientNoise4/Wave.cs that might help you, what differs from your code is that it aligns buffer lenght before use. I am putting read() function in Answer.
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    3. COUnfortunately, trying that code ends up going over the adjustment as 32768 % 2, 4, 16, and 32 (wasn't sure if align was bits or bytes) all come back 0
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