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PO
 

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    <p>You could implement this both in a breadth-first, and depth-first. I am gonna post a depth-first algorithm:</p> <pre><code>public class Node { private List&lt;Node&gt; parents = new ArrayList&lt;Node&gt;(); private List&lt;Node&gt; children = new ArrayList&lt;Node&gt;(); private Map&lt;Node, String&gt; receivedMessages = new HashMap&lt;Node, String&gt;(); private String id = ""; public Node(String id) { this.id = id; } void processMessage(Node sender, String message) { if (parents.contains(sender)) receivedMessages.put(sender, message); // if all the parents sent the message if (receivedMessages.size() == parents.size()) { String newMessage = composeNewMessage(receivedMessages); if (children.size() == 0) // if end node or "leaf" ouputResult(this, newMessage); else { for (Node child : children) { child.processMessage(this, newMessage); } } } } public void addParent(Node parent) { if (parent != null) parents.add(parent); parent.children.add(this); } public void addChild(Node child) { if (child != null) children.add(child); child.parents.add(this); } private void ouputResult(Node node, String newMessage) { // TODO: implement } private String composeNewMessage(Map&lt;Node, String&gt; receivedMessages2) { // TODO: implement return ""; } public static void main(String[] args) { Node A = new Node("A"); Node B = new Node("B"); Node C = new Node("C"); Node D = new Node("D"); Node start = new Node("start"); Node end = new Node("end"); A.addParent(start); B.addParent(A); C.addParent(A); D.addParent(B); D.addParent(C); end.addParent(D); A.processMessage(start, "Message"); } } </code></pre>
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    1. POHow to determine if a node has more than one input in a graph data structure?
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    1. USAlin Stoian
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    1. COI guess composeNewMessage() method doesn't need a parameter since it can access receivedMessages instance variable.
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      1. USChiron
    2. COyes.. sure. You said you wanted pseudo code, I put it so for clarification (composeNewMessage uses the receivedMessages). Remove it if code quality is of concert to you.
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    3. COHow can I get ride of start and end nodes?
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      1. USChiron
 

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