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    <p>There are several problems with your code I have tried to explain via the corrected and commented code here:</p> <h2>HTML &amp; JavaScript</h2> <pre><code>&lt;html&gt; &lt;head&gt;&lt;title&gt;pippo&lt;/title&gt; &lt;!-- added link to jQuery library --&gt; &lt;script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.6.4/jquery.min.js"&gt;&lt;/script&gt; &lt;!-- javascript can go here --&gt; &lt;script type="text/javascript"&gt; $.ajax({ type: "POST", url: "chgcontact.php", // use javascript object instead of `get` string to represent data data: {surname:user, name:'', tel:'', companymail:'', mail:'', fbid:''}, success: function(data){ // removed name,tel,companymail,mail,fbid alert(JSON.parse(data)); } }); return ""; } &lt;/script&gt; &lt;/head&gt; &lt;body&gt; Contact List: &lt;ul&gt; &lt;!-- removed `javascript` form onclick handler --&gt; &lt;li&gt;&lt;a href="#"&gt;&lt;img src="contacts/pippo.png" onclick="change('pippo')"/&gt;pippo&lt;/a&gt;&lt;/li&gt; &lt;li&gt;&lt;a href="#"&gt;&lt;img src="contacts/pluto.png" onclick="change('pluto')"/&gt;pluto&lt;/a&gt;&lt;/li&gt; &lt;li&gt;&lt;a href="#"&gt;&lt;img src="contacts/topolino.png" onclick="change('topolino')"/&gt;topolino&lt;/a&gt;&lt;/li&gt; &lt;/ul&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <h2>PHP</h2> <pre><code>&lt;?php $surname = $_POST['surname']; $result = mysql_query("select * from profile Where surname='$surname'") or die(mysql_error()); while ($row = mysql_fetch_array( $result )){ // create data object $data = new stdClass(); // add values to data object $data-&gt;name = ucfirst($row['name']); $data-&gt;tel = $row['telephone']; $data-&gt;companymail = $row['companymail']; $data-&gt;mail = $row['email']; $data-&gt;fbid = $row['facebook']; // send header to ensure correct mime type header("content-type: text/json"); // echo the json encoded data echo json_encode($data); } ?&gt; </code></pre> <p>All code is untested, but you should be able to see what I have done at each step. Good luck.</p>
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    1. POHow can I send JSON data from a PHP script to be used by jQuery?
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    1. USBilly Moon
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      1. VTUpMod
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    1. COThank you very much programmers, and especially to Billy Moon. I've only one question about the last step of json query, when you use JSON.parse(data), i've an error when i try to compile the page: JSON.parse: unexpected character alert(JSON.parse(data)); I think the problem is releated with the array recived in data, because it isn't a string, but a complex object. Could you help me again? Thanks in advance Billy
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    2. COactually, I think you need to use `JSON.stringify()` instead of `JSON.parse()` as you are trying to alert the result. I think I got confused before and put the wrong method.
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    3. COi've use now data.name and i have solve, it work perfectly, thank you very much, you have solve this bug, i've work about it, around 3 weeks XD
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