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POHow can I send JSON data from a PHP script to be used by jQuery?
 

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  1. POHow can I send JSON data from a PHP script to be used by jQuery?
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    <p>I have a problem with some JSON data. I don't know how to take some data generated in PHP and turn that into something that I can use in my jQuery script. The functionality I need is this: I need to be able to click on images on the page, and depending on the selected element, I need to show results from my DB.</p> <p>Here's the HTML page that I've got:</p> <pre><code>&lt;html&gt; &lt;head&gt; &lt;title&gt;pippo&lt;/title&gt; &lt;script&gt;&lt;!-- Link to the JS snippet below --&gt;&lt;/script&gt; &lt;/head&gt; &lt;body&gt; Contact List: &lt;ul&gt; &lt;li&gt;&lt;a href="#"&gt; &lt;img src="contacts/pippo.png" onclick="javascript:change('pippo')"/&gt;pippo &lt;/a&gt;&lt;/li&gt; &lt;li&gt;&lt;a href="#"&gt; &lt;img src="contacts/pluto.png" onclick="javascript:change('pluto')"/&gt;pluto &lt;/a&gt;&lt;/li&gt; &lt;li&gt;&lt;a href="#"&gt; &lt;img src="contacts/topolino.png" onclick="javascript:change('topolino')"/&gt;topolino &lt;/a&gt;&lt;/li&gt; &lt;/ul&gt; &lt;/body&gt; &lt;/html&gt; </code></pre> <p>Here's PHP code being called:</p> <pre><code>&lt;?php include('../dll/config.php'); $surname = $_POST['surname']; $result = mysql_query("select * from profile Where surname='$surname'") or die(mysql_error()); while ($row = mysql_fetch_array($result)) { $_POST['name'] = ucfirst($row['name']); $_POST['tel'] = $row['telephone']; $_POST['companymail'] = $row['companymail']; $_POST['mail'] = $row['email']; $_POST['fbid'] = $row['facebook']; } ?&gt; </code></pre> <p>Here's the Ajax JavaScript code I'm using:</p> <pre><code>&lt;script type="text/javascript"&gt; function change(user) { $.ajax({ type: "POST", url: "chgcontact.php", data: "surname="+user+"&amp;name=&amp;tel=&amp;companymail=&amp;mail=&amp;fbid", success: function(name,tel,companymail,mail,fbid){ alert(name); } }); return ""; } &lt;/script&gt; </code></pre> <p>Someone told me that this JS snippet would do what I want:</p> <pre><code>$.getJSON('chgcontact.php', function(user) { var items = [name,surname,tel,companymail,email,facebook]; $.each(user, function(surname) { items.push('surname="' + user + "'name='" + name + "'telephone='" + telephone + "'companymail='" + companymail + "'mail='" + mail + "'facebook='" + facebook); }); /* $('&lt;ul/&gt;', { 'class': 'my-new-list', html: items.join('') }).appendTo('body'); */ }); </code></pre> <p>But it is not clear to me - I don't understand how I need to use it or where I should include it in my code.</p>
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    1. COYour PHP script does nothing. `$_POST['tel']=$row['telephone'];` says you want to overwrite submitted data with data from a column in the database, that's it. you need an echo or something to show the data. right now your just moving data around.
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