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    <p>By using the <code>BitArray</code> class you can write</p> <pre><code>int a = Convert.ToInt32(Console.ReadLine()); byte[] numberAsByte = new byte[] { (byte)a }; BitArray bits = new BitArray(numberAsByte); </code></pre> <p>This converts the single bits of your byte to a <code>BitArray</code>, which represents an array of Booleans that can be handled in a easy way. Note that the constructor of <code>BitArray</code> accepts an array of bytes. Since we have only one byte, we have to pass it a byte array of length 1 containing this single byte (<code>numberAsByte</code>).</p> <p>Now let us count the bits that are set.</p> <pre><code>int count = 0; for (int i = 0; i &lt; 8; i++) { if (bits[i]) { count++; } } </code></pre> <p>Note that we simply test for a bit with <code>bits[i]</code>, which yields a Boolean value. The test <code>bits[i] == true</code> as being perfectly legal and correct yields the same result but is unnecessarily complicated. The <code>if</code> statement does not require a comparison. All it wants is a Boolean value.</p> <p>This calculates an odd parity bit. </p> <pre><code>if (count % 2 == 1) { // Odd number of bits bits[7] = true; // Set the left most bit as parity bit for even parity. } </code></pre> <p>The <code>%</code> operator is the modulo operator. It yields the rest of an integer division. <code>x % 2</code> yields <code>0</code> if <code>x</code> is even. If you want an odd parity bit, you can test <code>count % 2 == 0</code> instead.</p> <p><code>BitArray</code> has a <code>CopyTo</code> method which converts our bits back to an array of bytes (containing only one byte in our case).</p> <pre><code>bits.CopyTo(numberAsByte, 0); a = numberAsByte[0]; </code></pre> <p><code>numberAsByte[0]</code> contains our number with a parity bit.</p> <hr> <p>If you want the parity bit on the right side, then you will have to shift the number to the left by one bit first.</p> <pre><code>int a = Convert.ToInt32(Console.ReadLine()); a = a &lt;&lt; 1; // Do the parity bit calculation as above and, if necessary // set the right most bit as parity bit. bits[0] = true; </code></pre>
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    1. POC# Parity Bits from a Binary Number
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    1. COhttp://meta.stackexchange.com/questions/10811/how-to-ask-and-answer-homework-questions
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    2. CO@LB: OK, I will take that in account in the future. I have formulated my answer in a more didactical way. However, the link you provided also says, "Don't downvote others who answer homework questions in good faith, even if they break these guidelines".
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    3. CO@OlivierJacot-Descombes: I'm sorry to ask but it says that BitArray cannot be found. Also, I want to show the end binary number with parity as a result to the user.
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