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    <p>For one, this line of code:</p> <pre><code>if('object'==typeof(e)) </code></pre> <p>is like this in your code example:</p> <pre><code>if('object'==typeof(3)) </code></pre> <p>which is </p> <pre><code>if('object'=='number') </code></pre> <p>which will never match.</p> <p>I would also ask why you're trying to wrap a normal array in a jQuery object. It would be better to just use a method that operates on an array.</p> <p>As a global function, you could do it like this:</p> <pre><code>function removeArrayElement(array, itemToRemove) { for (var i = 0; i &lt; array.length; i++) { if (array[i] === itemToRemove) { array.splice(i, 1); break; } } } var x = ['a','b','c','d','e']; removeArrayElement(x, 'c'); </code></pre> <p>As a global method on the jQuery object, you could do it like this:</p> <pre><code>$.removeArrayElement = function(array, itemToRemove) { for (var i = 0; i &lt; array.length; i++) { if (array[i] === itemToRemove) { array.splice(i, 1); break; } } } var x = ['a','b','c','d','e']; $.removeArrayElement(x, 'c'); </code></pre> <p>As a method on the Array object, you could do it like this:</p> <pre><code>Array.prototype.removeElement = function(itemToRemove) { for (var i = 0; i &lt; this.length; i++) { if (this[i] === itemToRemove) { this.splice(i, 1); break; } } } var x = ['a','b','c','d','e']; x.removeElement('c'); </code></pre> <p>Working example of the prototype method here: <a href="http://jsfiddle.net/jfriend00/tEXWH/" rel="nofollow">http://jsfiddle.net/jfriend00/tEXWH/</a></p>
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    1. POremove given element in an array using jquery fn extension doesn't work in reference way
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    1. COhow to wrap up a normal array? can you explain little bit more detail?
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    2. CO@zannavi - Multiple examples added to my answer.
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    3. COprototype solution result in an error in my case, NOT_FOUND_ERR: DOM Exception 8: An attempt was made to reference a Node in a context where it does not exist. (mac osx safari 5.1.3 current version) i have not a clue for that. :(
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