Databases
StackOverflow2013
Postsdbo
PO
 

Note that there are some explanatory texts on larger screens.

plurals
  1. PO
    primarykey
    data
    text
    <p>You can also use numpy for this. Assuming you have:</p> <pre><code>dates = numpy.array([datetime(2012,02,03,12,00,00), datetime(2012,02,03,15,00,00), datetime(2012,02,03,13,00,00)]) values = numpy.array([[1, 1], [3, 3], [2, 2]]) </code></pre> <p>You can do at first:</p> <pre><code>unified = numpy.concatenate((dates.reshape(len(dates), 1), values), axis=1) </code></pre> <p>This will merge your two list, which considering what you want should be a better suited way to hold your data anyway. So now you have:</p> <pre><code>unified = array([[2012-02-03 12:00:00, 1, 1], [2012-02-03 15:00:00, 3, 3], [2012-02-03 13:00:00, 2, 2]], dtype=object) </code></pre> <p>Now you can do:</p> <pre><code>unified = numpy.sort(unified, axis=0) </code></pre> <p>This will sort after date. Now if you still want just the separate lists you can get them with: </p> <pre><code>unified[:, 0] &gt;&gt;&gt; array([2012-02-03 12:00:00, 2012-02-03 13:00:00, 2012-02-03 15:00:00], dtype=object) unified[:, 1:] &gt;&gt;&gt; array([[1, 1], [2, 2], [3, 3]], dtype=object) </code></pre> <p><strong>EDIT</strong> after your comment Ok now that I fully understand what you want you can achieve that by replacing</p> <pre><code> unified = numpy.sort(unified, axis=0) </code></pre> <p>with:</p> <pre><code> unified = numpy.array(sorted(unified, key= lambda x: x[0])) </code></pre> <p><strong>EDIT</strong></p> <p>have you tried what I just suggested? In my terminal:</p> <pre><code> unified = numpy.array([[datetime(2012,02,03,12,00,00), 4, 1],[datetime(2012,02,03,15,00,00), 5, 2],[datetime(2012,02,03,13,00,00), 2, 1]], dtype=object) &gt;&gt;&gt; unified array([[2012-02-03 12:00:00, 4, 1], [2012-02-03 15:00:00, 5, 2], [2012-02-03 13:00:00, 2, 1]], dtype=object) &gt;&gt;&gt; unified = numpy.array(sorted(unified, key=lambda x: x[0])) &gt;&gt;&gt; unified array([[2012-02-03 12:00:00, 4, 1], [2012-02-03 13:00:00, 2, 1], [2012-02-03 15:00:00, 5, 2]], dtype=object) </code></pre>
    singulars
    1. This table or related slice is empty.
    1. PONumpy sorting by increasing datetime
      singulars
      1. PTQuestion
    1. PTAnswer
    1. USBogdan
    1. USBogdan
    plurals
    1. This table or related slice is empty.
    1. This table or related slice is empty.
    1. PONumpy sorting by increasing datetime
      singulars
      1. PTQuestion
    1. This table or related slice is empty.
    1. VO
      singulars
      1. PO
      1. This table or related slice is empty.
      1. VTAcceptedByOriginator
    2. VO
      singulars
      1. PO
      1. This table or related slice is empty.
      1. VTUpMod
    3. VO
      singulars
      1. PO
      1. This table or related slice is empty.
      1. VTUpMod
    1. COThis is almost that. But this is also sorting all the columns by increasing order. I only want according to time unless I messed up my measurements .... I'll take a look on numpy.sort documentation...
      singulars
      1. PO
      1. USuser1187727
    2. CONot so obvious problem... This representation is nice : `unified = array([[2012-02-03 12:00:00, 1, 1],[2012-02-03 15:00:00, 3, 3],[2012-02-03 13:00:00, 2, 2]], dtype=object)` But my case is for example from `unified = array([[2012-02-03 12:00:00, 4, 1],[2012-02-03 15:00:00, 5, 2],[2012-02-03 13:00:00, 2, 1]], dtype=object)` I want to obtain `array([[2012-02-03 12:00:00, 4, 1],[2012-02-03 13:00:00, 2, 1],[2012-02-03 15:00:00, 5, 2]], dtype=object)`
      singulars
      1. PO
      1. USuser1187727
    3. COTHIS IS EXACTLY WHAT I WANTED TO OBTAIN !!! THANK YOU. (This should be implemented in an option of numpy.sort function.)
      singulars
      1. PO
      1. USuser1187727
 

Querying!

 
Guidance
A row detail

Detail views are divided into sections. All the information in the data section comes from columns in the selected row. The other sections display data from other, related rows.

Related data can be related in a to-one or a to-many fashion. Captions of data related in a to-many fashion link to a list view showing a filtered view of the table.

Try moving around until you find a non-empty to-many entry and click on the label to get to one. You can move back to the root by clicking on the database name in the header.

SQuiL has stopped working due to an internal error.

If you are curious you may find further information in the browser console, which is accessible through the devtools (F12).

Reload