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    <p>You could solve this on the database level with a view, which would be the correct method anyway.</p> <pre><code>CREATE VIEW with_inverse_animal_friends ( SELECT id, animal_id, animal_friend_id, created_at, updated_at, status_id FROM animal_friends UNION SELECT id, animal_friend_id AS animal_id, animal_id AS animal_friend_id, created_at, updated_at, status_id FROM animal_friends ) </code></pre> <p>If you dont want to have double entries for friends with relations both ways you could do this:</p> <pre><code>CREATE VIEW unique_animal_friends ( SELECT MIN(id), animal_id, animal_friend_id, MIN(created_at), MAX(updated_at), MIN(status_id) FROM (SELECT id, animal_id, animal_friend_id, created_at, updated_at, status_id FROM animal_friends UNION SELECT id, animal_friend_id AS animal_id, animal_id AS animal_friend_id, created_at, updated_at, status_id FROM animal_friends) AS all_animal_friends GROUP BY animal_id, animal_friend_id ) </code></pre> <p>You would need a way to decide which status_id to use in case there are two conflicting ones. I chose MIN(status_id) but that is probably not what you want.</p> <p>In Rails you can do this now:</p> <pre><code>class Animal &lt; ActiveRecord::Base has_many :unique_animal_friends has_many :friends, :through =&gt; :unique_animal_friends end class UniqueAnimalFriend &lt; ActiveRecord::Base belongs_to :animal belongs_to :friend, :class_name =&gt; "Animal" end </code></pre> <p>This is out of my head and not tested. Also, you might need some plugin for view handling in rails (like "redhillonrails-core").</p>
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    1. COThanks, I like the idea ! I'll test as soon as I can and let you know.
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    2. COSorry for the loooooooong delay before replying to this, I finally had time to test your solution, and it works like a charm, out of the box.
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