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POSubmitting From jQuery to PHP
 

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    <p>I have sent data to my jquery file and I tested the data string and everything is stored where it should be but when I post it to my php file all the variables are null. Can someone help me? </p> <pre><code>$(document).ready(function() { $(".button").click(function() { //$('.error').hide(); var firstname = $("input#First_Name").val(); var lastname = $("input#Last").val(); var areacode = $("input#area_code").val(); var phonenumber = $("input#Phone_Number").val(); var emailaddress = $("input#emailaddress").val(); var confirmemail = $("input#confirm_email").val(); var password = $("input#Password_Input").val(); var confirmpassword = $("input#ConfirmPassword").val(); var streetaddress = $("input#StreetAddress_input").val(); var streetaddress2 = $("input#StreetAddress2_input").val(); var city = $("input#City_Input").val(); var state = $("input#StateInput").val(); var zipcode = $("input#ZipCode").val(); var month = $("input#month_input").val(); var day = $("input#day_input").val(); var year = $("input#year_input").val(); var services = $("input#services_input").val(); var agreement = $("input#agreement").val(); var dataString = 'firstname=' + firstname + '&amp;lastname=' + lastname + '&amp;areacode=' + areacode + '&amp;phonenumber=' + phonenumber + '&amp;emailaddress=' + emailaddress + '&amp;confirmemail=' + confirmemail + '&amp;password=' + password + '&amp;streetaddress=' + streetaddress + '&amp;streetaddress2=' + streetaddress2 + '&amp;city=' + city + '&amp;state=' + state + '&amp;zipcode=' + zipcode + '&amp;month=' + month + '&amp;day=' + day + '&amp;year=' + year + '&amp;services=' + services + '&amp;agreement=' + agreement; alert(dataString); $.ajax({ type: "POST", url: "http://www.vectorcreditsolution.com/js/process.php", data: dataString, success: function() { alert("Yay it was sent"); } }); return false; }); </code></pre> <p>and then my php file</p> <pre><code>&lt;?php $FirstName = $_POST["firstname"]; $LastName = $_POST['lastname']; $AreaCode = $_POST['areacode']; $PhoneNumber = $_POST['phonenumber']; $EmailAddress = $_POST['emailaddress']; $Password = $_POST['password']; $StreetAddress = $_POST['streetaddress']; $StreetAddress2 = $_POST['streetaddress2']; $City= $_POST['city']; $State = $_POST['state']; $ZipCode = $_POST['zipcode']; $Month = $_POST['month']; $Day = $_POST['day']; $Year= $_POST['year']; $Service=$_POST['services']; var_dump($_POST["firstname"]); var_dump($_POST['firstname']); var_dump($_POST[firstname]); </code></pre>
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    1. COInstead of doing this manually, use [ajaxForm or serialize](http://stackoverflow.com/a/1960245/797303)
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    2. COSilly Question: What steps are you taking to view your PHP file to test if $_POST is populated? Are you using firebug to check the response?
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    3. COoh I used the var_dump
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