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POHow to find minimum and maximum of cartesian co-ordinates in Scala
 

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  1. POHow to find minimum and maximum of cartesian co-ordinates in Scala
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    <p>I am trying to solve GameOfLife in Scala where I have an infinte grid. I am trying to represent the grid as a Set of Cell(x,y). When I read from say String I start at (0,0). But because of the laws of GameOfLife and since I am considering Infinite Grid after having applied rules to my Generation class I want to print current generation.</p> <p>Here I am not sure how to calculate the minimum position (read x,y iterators) from where to start iterating and printing either 'X' for alive cell and '-' for dead cell in GameOfLife for that Generation.I am supplying my naive solution of toString method of Generation class. But I am not at all happy with it. Can somebody suggest be a better succient solution?</p> <pre><code>override def toString:String = { val output:StringBuilder = new StringBuilder(); val minOfRowColumn = for { cell &lt;- aliveCells row = cell.row column = cell.column } yield if( row &lt; column ) row else column val min = minOfRowColumn.min val maxOfRowColumn = for { cell &lt;- aliveCells row = cell.row column = cell.column } yield if( row &gt; column ) row else column val max = maxOfRowColumn.max var row = min; var column = min; while(row &lt;= max) { while(column &lt;= max) { if(aliveCells.contains(Cell(row,column))) { output.append('X') } else output.append('-') column = column + 1 } output.append("\n"); column = min row = row + 1 } //remove the last new line addded. val indexOfNewLine = output.lastIndexOf("\n"); if( -1 != indexOfNewLine ) output.delete(indexOfNewLine,output.length()); return output.toString(); } </code></pre> <p>aliveCells here is a Set[Cell] where Cell is Cell(x,y) a case class.</p>
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