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  1. POEach Radiobutton for each form or 1 Form for all radiobuttons?
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    <p>i have a problem with this homepage.</p> <p>I have to create a Site like this:</p> <pre><code>status create work finished Item1 * o o Item2 o * o Item3 o o * </code></pre> <p>(* = checked, o = unchecked)</p> <p>Now as admin i have the rights to change the status of the each Item.</p> <p>For example when i change the Status from Item1 to "work" it should send a Form and update it in Database.</p> <p>My Problem is know, should i create for each pair of 3 radiobuttons 1 Form?</p> <p>But when i create 1 for all Buttons i will have problems to know which status have changed.<br> Only compare with each Database entry.</p> <p>Before someone ask, i should use radiobuttons. Hope someone could help.</p> <p>Greetz</p> <p>Demonking</p> <p>Edit: Sorry, eomeone have misunderstand me. I meant if i would be faster and better with :</p> <pre><code>&lt;form method="post"&gt; Item 1 &lt;input type="radio" name="item1" value="create" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item1" value="work" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item1" value="finished" onclick="this.form.submit()"/&gt; &lt;/form&gt; &lt;form method="post"&gt; Item 2 &lt;input type="radio" name="item2" value="create" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item2" value="work" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item2" value="finished" onclick="this.form.submit()"/&gt; &lt;/form&gt; </code></pre> <p>or </p> <pre><code>&lt;form method="post"&gt; Item 1 &lt;input type="radio" name="item1" value="create" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item1" value="work" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item1" value="finished" onclick="this.form.submit()"/&gt; Item 2 &lt;input type="radio" name="item2" value="create" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item2" value="work" onclick="this.form.submit()"/&gt; &lt;input type="radio" name="item2" value="finished" onclick="this.form.submit()"/&gt; &lt;/form&gt; </code></pre> <p>because of Performance with PHP/MySQL</p>
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