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    <p>If you want to use <code>super</code> in <code>child</code> to call <code>parent.__init__</code> and <code>parent2._init__</code>, then both parent <code>__init__</code>s must also call <code>super</code>:</p> <pre><code>class parent(Base): def __init__(self,x=1,y=2): super(parent,self).__init__(x,y) class parent2(Base): def __init__(self,x=3,y=4): super(parent2,self).__init__(x,y) </code></pre> <p>See <a href="https://stackoverflow.com/q/5033903/190597">"Python super method and calling alternatives"</a> for more details on the sequence of calls to <code>__init__</code> caused by using <code>super</code>.</p> <hr> <pre><code>class Base(object): def __init__(self,*args): pass class parent(Base): var1=1 var2=2 def __init__(self,x=1,y=2): super(parent,self).__init__(x,y) self.var1=x self.var2=y class parent2(Base): var4=11 var5=12 def __init__(self,x=3,y=4): super(parent2,self).__init__(x,y) self.var4=x self.var5=y def parprint(self): print self.var4 print self.var5 class child(parent, parent2): var3=5 def __init__(self,x,y): super(child, self).__init__(x,y) childobject = child(9,10) print childobject.var1 print childobject.var2 print childobject.var3 childobject.parprint() </code></pre> <hr> <p>You might be wondering, "Why use <code>Base</code>?". If <code>parent</code> and <code>parent2</code> had inherited directly from <code>object</code>, then <code>super(parent2,self).__init__(x,y)</code> would call <code>object.__init__(x,y)</code>. That raises a <code>TypeError</code> since <code>object.__init__()</code> takes no parameters.</p> <p>To workaround this issue, you can make a class <code>Base</code> which accepts arguments to <code>__init__</code> but does not pass them on to <code>object.__init__</code>. With <code>parent</code> and <code>parent2</code> inheriting from <code>Base</code>, you avoid the <code>TypeError</code>.</p>
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