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POsimple C code giving segmentation fault on gcc
 

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    <p>I found a question somewhere ... here it is and its answer with explanation.</p> <pre><code>main() { char *p="hai friends",*p1; p1=p; while(*p!='\0') ++*p++; printf("%s %s",p,p1); } Answer: ibj!gsjfoet Explanation: ++*p++ will be parse in the given order </code></pre> <p>*p that is value at the location currently pointed by p will be taken </p> <p>++*p the retrieved value will be incremented </p> <p>when ; is encountered the location will be incremented that is p++ will be executed</p> <p>Hence, in the while loop initial value pointed by p is ‘h’, which is changed to ‘i’ by executing ++*p and pointer moves to point, ‘a’ which is similarly changed to ‘b’ and so on. Similarly blank space is converted to ‘!’. Thus, we obtain value in p becomes “ibj!gsjfoet” and since p reaches ‘\0’ and p1 points to p thus p1 doesnot print anything.</p> <p>I found something wrong with explanation on p1.I think p1 should print "hai friends" and output of p is fine as given.</p> <p>but when I tried to run the same code on gcc compiler,its giving <strong>segmentatiion fault</strong></p> <p>here is the exact code which I tried to run ..</p> <pre><code> #include&lt;stdio.h&gt; int main() { char *p="hai friends",*p1; p1=p; while(*p !='\0') ++*p++; printf("%s %s",p,p1); return 0; } </code></pre> <p>If possible edit the title ,I could not find a suitable title which would explain the situation more clearly.</p> <p><strong>EDIT :</strong></p> <p>I tried to run the modified code as suggested by <strong>Mysticial</strong> ,But what I think output should be -</p> <pre><code>ibj!gsjfoet hai friends </code></pre> <p>because I am incrementing only p0 but p1 should be as its initial place i.e. at the starting address of string.Please if anyone could explain it where I am getting it wrong ???</p>
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    1. COThis *must* be a duplicate. To lazy to search for it though.
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