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POAjax call failing in Django
 

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  1. POAjax call failing in Django
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    <p>I have the following ajax call to update a particular field of a model</p> <pre><code>$("#updateLink").click(function(){ var dec_text = $('#desc_text').val(); $.ajax({ type: "POST", url:"/users/update_desc/", data: { 'val': dec_text, }, success: function(){ $(".display, .edit").toggle(); $("#descText").html(dec_text); }, error: function(){ alert("Error"); }, }); return false; }); </code></pre> <p>and my view is this </p> <pre><code>@csrf_exempt def update_desc(request): if request.is_ajax(): if request.method == 'POST': desc_text = request.POST.get('val', False) if desc_text: profile = user.profile profile.desc = desc_text profile.save() return_message = "Sent mail" return HttpResponse(return_message,mimetype='application/javascript') </code></pre> <p>I am constantly getting an error message and I don't know how to solve this. I even used the <code>csrf_exempt</code> decorator to workaround if the problem was caused by a missing <code>csrf token</code> but still the problem persists.</p> <p>Except one <code>ajax post</code> which in my <code>base</code> template all the ajax calls are failing. Can anybody please help to understand what is happening here. I can give some more details if required.</p> <p><strong>Edit:</strong></p> <p>I have added the a <code>js</code> file containing this <a href="https://docs.djangoproject.com/en/dev/ref/contrib/csrf/#ajax">https://docs.djangoproject.com/en/dev/ref/contrib/csrf/#ajax</a> in my base template, so it means it is present in all my templates. And I am using django 1.3 version. </p>
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    1. COI am expecting that you are still getting the csrf_token missing error. If so my answer is posted below else state the error after you are used csrf_exempt.
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      1. USZain Khan
    2. COActually I do not know how to get the error, as you can see I have just put an alert in my `error` callback which tells me that my ajax call failed but it does not tell me what the error was. How can I get the error?
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      1. USSachin
    3. COFirstly, in your settings.py file DEBUG = True. This would not display your ajax errors but definitely others which are not catered.
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      1. USZain Khan
 

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