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    <p>Consider the following self commented code. I tried to keep in simple</p> <pre><code>&gt;&gt;&gt; from fractions import Fraction &gt;&gt;&gt; def Arch2Float(num): #First Partition from Right so that the Feet and Unit always #Remains aligned even if one of them is absent ft,x,inch=num.rpartition("\'") #Convert the inch to a real and frac part after stripping the #inch (") identifier. Note it is assumed that the real and frac #parts are delimited by '-' real,x,frac=inch.strip("\"").rpartition("-") #Now Convert every thing in terms of feet which can then be converted #to float. Note to trap Error's like missing or invalid items, its better #to convert each items seperately result=0 try: result = int(ft.strip("\'")) except ValueError: None #Convert the real inch part as a fraction of feet try: result += Fraction(int(real),12) except ValueError: None #Now finally convert the Fractional part using the fractions module and convert to feet try: result+=Fraction(frac)/12 except ValueError: None return float(result) </code></pre> <p>Acid Test</p> <pre><code>&gt;&gt;&gt; print Arch2Float('15-3/4"') # 15-3/4" (without ft) 1.3125 &gt;&gt;&gt; print Arch2Float('12\' 6-3/4"') #12' 6-3/4" 12.5625 &gt;&gt;&gt; print Arch2Float('12\'6-3/4"') #12'6-3/4" (without space) 12.5625 &gt;&gt;&gt; print Arch2Float('3/4"') #3/4" (just the inch) 0.0625 &gt;&gt;&gt; print Arch2Float('15\'') #15' (just ft) 15.0 &gt;&gt;&gt; print Arch2Float('15') #15 (without any ascent considered as inch) 1.25 </code></pre> <p>Converting from Float to Architecture would be easy as you don't have to take the pain to parsing</p> <pre><code>&gt;&gt;&gt; def Float2Arch(num): num=Fraction(num) ft,inch=Fraction(num.numerator/num.denominator),Fraction(num.numerator%num.denominator)/num.denominator*12 real,frac=inch.numerator/inch.denominator,Fraction(inch.numerator%inch.denominator,inch.denominator) return '{0}\' {1}-{2}"'.format(ft,real,frac) </code></pre> <p>Acid Test</p> <pre><code>&gt;&gt;&gt; print Float2Arch(Arch2Float('12\' 6-3/4"')) 12' 6-3/4" &gt;&gt;&gt; print Float2Arch(Arch2Float('15-3/4"')) 1' 3-3/4" &gt;&gt;&gt; print Float2Arch(Arch2Float('12\'6-3/4"')) 12' 6-3/4" &gt;&gt;&gt; print Float2Arch(Arch2Float('3/4"')) 0' 0-3/4" &gt;&gt;&gt; print Float2Arch(Arch2Float('15\'')) 15' 0-0" &gt;&gt;&gt; print Float2Arch(Arch2Float('15')) 1' 3-0" &gt;&gt;&gt; </code></pre> <p>Note*** Its important to keep the float representation in either the lowest denominator (inch) or the highest represented denominator (feet). I opted for the highest in this case feet. If you wan't to lower it you can multiply it by 12.</p> <hr> <p>Update to cater Rounding Request (Not sure if this is elegant but does the Job)</p> <pre><code>def Float2Arch(num): num=Fraction(num) ft,inch=Fraction(num.numerator/num.denominator),Fraction(num.numerator%num.denominator)/num.denominator*12 real,frac=inch.numerator/inch.denominator,Fraction(inch.numerator%inch.denominator,inch.denominator) for i in xrange(1,17): if Fraction(frac) &lt; Fraction(1.0/16*i): break frac=Fraction(1.0/16*i) if frac&gt;= 1: real+=1 frac=0 return '{0}\' {1}-{2}"'.format(ft,real,frac) </code></pre>
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    1. POHow to convert a measurement displayed in an architectural format to a floating point?
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    1. USAbhijit
    1. USAbhijit
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      1. VTUpMod
    1. COPer @Keith's comment, I would add unit to this and turn the float into a struct or class with a float and a unit.
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      1. USJesse Smith
    2. CO@JesseSmith, You just need to convert it to a string and add the unit. For ex `str(Arch2Float('12\' 6-3/4"'))+ ' ft'`
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      1. USAbhijit
    3. CO@Abhijit, this solutions works as well. I have combined @RaymondHettinger with your `Float2Arch` function. How would you suggest rounding the returned value so an input like this **18.33** returns **18' 4"**?
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      1. USClayton
 

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