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    <p>This is a three part answer</p> <h2>Part one</h2> <p>First, use the <code>TIMEFORMAT</code> variable to output only seconds elapsed. Then you can add this directly</p> <p>From <code>man bash</code></p> <blockquote> <p><strong>TIMEFORMAT</strong> The value of this parameter is used as a format string specifying how the timing information for pipelines prefixed with the time reserved word should be displayed. The % character introduces an escape sequence that is expanded to a time value or other information. The escape sequences and their meanings are as follows; the braces denote optional portions.</p> </blockquote> <p>Here is an example which outputs only seconds with a precision of 0, i.e. no decimal point. Read part three why that's important.</p> <pre><code>TIMEFORMAT='%0R'; time sleep 1 1 </code></pre> <h2>Part two</h2> <p>Second, how do we capture the output of <code>time</code>? It's actually a bit tricky, here's how you do capture the time from the command above</p> <pre><code>TIMEFORMAT='%0R'; time1=$( { time sleep 1; } 2&gt;&amp;1 ) </code></pre> <h2>Part three</h2> <p>How do we add the times together and get the average?</p> <p>In bash we use the <code>$(( ))</code> construct to do math. Note that <code>bash</code> does not natively support floating point so you will be doing integer division (hence the precision 0.) Here is a script that will capture the <code>time</code> from two commands and output each of the individual times and their average</p> <pre><code>#!/bin/bash TIMEFORMAT='%0R' time1=$( { time sleep 1; } 2&gt;&amp;1 ) time2=$( { time sleep 4; } 2&gt;&amp;1 ) ave=$(( (time1 + time2) / 2)) echo "time1 is $time1 | time2 is $time2 | average is $ave" </code></pre> <h3>Output</h3> <pre><code>time1 is 1 | time2 is 4 | average is 2 </code></pre> <p>If integer division is a non-starter for you and you want precision, as long as you don't mind calling the external binary <code>bc</code>, you can do this quite easily. </p> <pre><code>#!/bin/bash TIMEFORMAT='%3R' time1=$( { time sleep 1; } 2&gt;&amp;1 ) time2=$( { time sleep 4; } 2&gt;&amp;1 ) ave=$( bc &lt;&lt;&lt;"scale=3; ($time1 + $time2)/2" ) echo "time1 is $time1 | time2 is $time2 | average is $ave" </code></pre> <h3>Output</h3> <pre><code>time1 is 1.003 | time2 is 4.003 | average is 2.503 </code></pre>
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    1. POHow to add two time outputs in bash
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    1. COThanks, it is exactly what I wanted.
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    2. COReally nice explanation. I wanted to the answer for this question too. +1 :)
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    3. CO@OctavianRinciog I'm glad this is what you wanted. If this answer is sufficient for you, please click on the checkmark to the left of my answer to accept it.
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