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POjquery ui slider - ignore/do not step to increment
 

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    <blockquote> <p><strong>Possible Duplicate:</strong><br> <a href="https://stackoverflow.com/questions/8646796/jquery-ui-slider-max-value-not-end-of-slider">jQuery UI Slider - max value (not end of slider)</a> </p> </blockquote> <p>I'm using non-linear increments for my ui slider:</p> <pre><code> $(function() { var trueValues = [5, 10, 20, 50, 100, 150, 165]; var values = [10, 20, 30, 40, 60, 90, 100]; var slider = $("#parkSlider").slider({ orientation: 'horizontal', range: "min", value: 40, slide: function(event, ui) { var includeLeft = event.keyCode != $.ui.keyCode.RIGHT; var includeRight = event.keyCode != $.ui.keyCode.LEFT; var value = findNearest(includeLeft, includeRight, ui.value); slider.slider('value', value); $("#amount").val(getRealValue(value)); return false; }, }); function findNearest(includeLeft, includeRight, value) { var nearest = null; var diff = null; for (var i = 0; i &lt; values.length; i++) { if ((includeLeft &amp;&amp; values[i] &lt;= value) || (includeRight &amp;&amp; values[i] &gt;= value)) { var newDiff = Math.abs(value - values[i]); if (diff == null || newDiff &lt; diff) { nearest = values[i]; diff = newDiff; } } } return nearest; } function getRealValue(sliderValue) { for (var i = 0; i &lt; values.length; i++) { if (values[i] &gt;= sliderValue) { return trueValues[i]; } } return 0; } }); </code></pre> <p>I want to ignore the value at 165, and not step to that increment - so the slider can only max at 150, although 150 is not the max value of the slider.</p> <p>A graphic may explain better:</p> <p><img src="https://i.stack.imgur.com/5VGma.png" alt="slider"></p> <p>where I want the position of the slider handle to stop at the 150 value, and not step to the 165 value. (I know I can set the max of the slider, but this is the wrong behavior, as the slider handle then extends past the 150 tick mark)</p>
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      1. USlolmaus - Andrey Mikhaylov
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    1. CObecause the approach for this answer is somewhat different
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    2. COMy answer for this would be exactly the same as my answer to the other question (which has now been updated).
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      1. USJosh Smith
 

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