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    <p>Yes, you will need create your own user provider and add it as a service your Symfony app. The user provider class you create must implement the UserProviderInterface </p> <p>To get your class started here is an example of my custom class located in Namespace/Bundle/Security/Provider.php:</p> <pre><code>namespace CB\WebsiteBundle\Security; use Symfony\Component\Security\Core\User\UserInterface; use Symfony\Component\Security\Core\User\UserProviderInterface; use Symfony\Component\Security\Core\Exception\UsernameNotFoundException; use CB\WebsiteBundle\Entity\User; class Provider implements UserProviderInterface { protected $user; public function __contsruct (UserInterface $user) { $this-&gt;user = $user; } /** * Loads the user for the given username. * * This method must throw UsernameNotFoundException if the user is not * found. * * @throws UsernameNotFoundException if the user is not found * @param string $username The username * * @return UserInterface */ function loadUserByUsername($username) { $user = User::find(array('username'=&gt;$username)); if(empty($user)){ throw new UsernameNotFoundException('Could not find user. Sorry!'); } $this-&gt;user = $user; return $user; } /** * Refreshes the user for the account interface. * * It is up to the implementation if it decides to reload the user data * from the database, or if it simply merges the passed User into the * identity map of an entity manager. * * @throws UnsupportedUserException if the account is not supported * @param UserInterface $user * * @return UserInterface */ function refreshUser(UserInterface $user) { return $user; } /** * Whether this provider supports the given user class * * @param string $class * * @return Boolean */ function supportsClass($class) { return $class === 'MC\WebsiteBundle\Entity\User'; } } </code></pre> <p>Some key things to note in this class is that it uses a custom User entity that you would define yourself which would facilitate the connection to your Java middleware. In my case, I am connecting to a REST api to get my user information and my user class uses the User::find($criteria) static function to find users by username.</p> <p>Once you have your own User class that interacts with your middleware, and you have your new provider, you need to add the provider as a service in your bundle configuration: YourBundle/Resources/config.xml:</p> <pre><code>&lt;parameters&gt; &lt;parameter key="cb_security_user.class"&gt;CB\WebsiteBundle\Entity\User&lt;/parameter&gt; &lt;parameter key="cb_security_provider.class"&gt;CB\WebsiteBundle\Security\Provider&lt;/parameter&gt; &lt;/parameters&gt; &lt;services&gt; &lt;service id="cb_security_user" class="%cb_security_user.class%" /&gt; &lt;service id="cb_security_provider" class="%cb_security_provider.class%"&gt; &lt;argument type="service" id="cb_security_user" /&gt; &lt;/service&gt; &lt;/services&gt; </code></pre> <p>You can find more details on my blog post here: <a href="http://clintberry.com/2011/custom-user-providers-symfony2/" rel="nofollow">Custom User Providers in Symfony2</a></p> <p>Hope this helps!</p>
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    1. POHow to create a custom User-Provider for symfony2?
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    1. COI ran across this answer because it was flagged as possibly inappropriate. Clint, it's generally not considered appropriate to link to content (especially your own content) without any further elucidating information. You should either delete this answer (and the exact copy posted [here](http://stackoverflow.com/questions/8577529/symfony-2-custom-user-provider/8593824#8593824)) or summarize your solution here.
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      1. USMichael Petrotta
    2. COThank you for informing me. I think I have done that before. I will go through my answers and make sure to remove link-only content.
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    3. CO@michael - I edited my answer, does that help?
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