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primarykey
Id
8573713
data
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0
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9
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2011-12-20T10:02:27.900
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2011-12-20T10:44:56.040
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2011-12-20T10:44:56.040
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218196
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218196
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8573668
PostTypeId
2
Score
6
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0
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text
Body
New answer Regarding your example I'd say it is really easier to split the string and iterate over it: <pre><code>function filter(str, delim, test) { var parts = str.split(delim), result = []; for(var i = 0, len = parts.length; i < len; i++) { if(test(parts[i])) result.push(parts[i]); } return result.join(delim); } str = filter(str, ', ', function(s) { s = s.toLowerCase(); return s === 'bair hugger' || s === 'fluid warmer'; }); </code></pre> Otherwise, your expression becomes something like this: <pre><code>new RegExp("(^|, )(?!(?:Bair Hugger|Fluid Warmer)(?:$|, )).+?(, |$)", "i"); </code></pre> and you have to use a callback for the replacement to decide whether to remove the preceding <code>,</code> or trailing <code>,</code> or not: <pre><code>str = str.replace(re_comma, function(str, pre, tail) { return pre && tail ? tail : '';// middle of the string, leave one }); </code></pre> The intention of this code is less clear. Maybe there is a simpler expression, but I think filtering the array is still cleaner. <hr> Old answer: (doesn't solve the problem at hand but provides information regarding regular expressions). <code>[]</code> denotes a character class and will only match one character out of the ones you provided. <code>[^Bair Hugger|Fluid Warmer]</code> is the same as <code>[^Bair Huge|FldWm]</code>. You could use a negative lookahead: <pre><code>new RegExp("^(?!(Bair Hugger|Fluid Warmer), ).+?, $", "i"); </code></pre> Note that you have to use <code>\\</code> inside a string to produce one <code>\</code>. Otherwise, <code>"\w"</code> becomes <code>w</code> and is not a special character sequence anymore.You also have to anchor the expression. Update: As you mentioned you want to match any string before the comma, I decided to use <code>.</code> instead of <code>\w</code>, to match any character.
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