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8522600
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0
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2011-12-15T15:36:29.317
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2012-12-13T15:18:10.213
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2012-12-13T15:18:10.213
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897399
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457316
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2
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16
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<p>If you provider does not support Invoke and you need to combine two expression, you can use an ExpressionVisitor to replace the parameter in the second expression by the parameter in the first expression.</p> <pre><code>class ParameterUpdateVisitor : ExpressionVisitor { private ParameterExpression _oldParameter; private ParameterExpression _newParameter; public ParameterUpdateVisitor(ParameterExpression oldParameter, ParameterExpression newParameter) { _oldParameter = oldParameter; _newParameter = newParameter; } protected override Expression VisitParameter(ParameterExpression node) { if (object.ReferenceEquals(node, _oldParameter)) return _newParameter; return base.VisitParameter(node); } } static Expression<Func<T, bool>> UpdateParameter<T>( Expression<Func<T, bool>> expr, ParameterExpression newParameter) { var visitor = new ParameterUpdateVisitor(expr.Parameters[0], newParameter); var body = visitor.Visit(expr.Body); return Expression.Lambda<Func<T, bool>>(body, newParameter); } [TestMethod] public void ExpressionText() { string text = "test"; Expression<Func<Coco, bool>> expr1 = p => p.Item1.Contains(text); Expression<Func<Coco, bool>> expr2 = q => q.Item2.Contains(text); Expression<Func<Coco, bool>> expr3 = UpdateParameter(expr2, expr1.Parameters[0]); var expr4 = Expression.Lambda<Func<Recording, bool>>( Expression.OrElse(expr1.Body, expr3.Body), expr1.Parameters[0]); var func = expr4.Compile(); Assert.IsTrue(func(new Coco { Item1 = "caca", Item2 = "test pipi" })); } </code></pre>
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1. POCombining two expressions (Expression<Func<T, bool>>)
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1. COThis solved my particular problem where the other solution resulted in the same exception. Thanks.
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  USShaun Wilson

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