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  1. PO
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    <p>I'm not 100% sure what you're asking, but:</p> <p>To check if it's an integral <strong>type</strong>, use this: <code>if (obj is float || obj is double)</code>, or <code>if typeof(T) == typeof(float) || typeof(T) == typeof(double))</code></p> <p>To check if it's an integral <strong>value</strong>, cast it to a double, and then do <code>if(value == Math.Round(value))</code></p> <p>Of course, that is assuming that you have a number in the first place. I believe that the Operator class you're using supports things like DateTime. Would it be better to make your generic method have a generic constraint <a href="http://msdn.microsoft.com/en-us/library/system.iconvertible.aspx" rel="nofollow"><code>where T : IConvertible</code></a>? That way there'd be explicit <code>ToDouble</code> and <code>ToInteger</code> methods.</p> <p><strong>Edit</strong>:</p> <p>I think I understand: you've got two local variables, <code>double d; T num;</code>. You want to cast <code>d</code> to type <code>T</code>, but with proper rounding if <code>T</code> is a integral type. Is that correct?</p> <p>Assuming that's correct, here's what I'd do:</p> <pre><code>public void SomeMethod&lt;T&gt;() { double d; // I think I got all the floating-point types. There's only a few, so we can test for them explicitly. if(typeof(T) != typeof(double) &amp;&amp; typeof(T) != typeof(float) &amp;&amp; typeof(T) != typeof(Decimal)) { d = Math.Round(d); } T converted = Convert.ChangeType(d, typeof(T)); } </code></pre>
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    1. POHow to check whether a (generic) number type is an integral or nonintegral type in C#?
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    1. USDavid Yaw
    1. USDavid Yaw
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    1. COConcerning `IConvertible`, not a bad idea at all. Am considering it now. Checking the type explicitly is what I wanted to avoid.
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      1. USSteven Jeuris
    2. CO... however, that doesn't solve my actual issue which is mentioned in the example. ;p I need to check whether it is nonintegral so that I now whether or not I have to round the value.
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      1. USSteven Jeuris
    3. COSo if the result is not a whole number, you want to round it to a whole number, is that it?
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      1. USDavid Yaw
 

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