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    <blockquote> <p>Where does size_t come from when I don't have anything included in an empty project?</p> </blockquote> <p>If you don't have anything included, then you can't use <code>size_t</code>. It's defined in <code>&lt;stddef.h&gt;</code> (and perhaps also in <code>&lt;cstddef&gt;</code>, if your version of that header puts the definitions in the global namespace as well as <code>std</code>).</p> <blockquote> <p>Is it reasonable to always assume size_t == std::size_t?</p> </blockquote> <p>Yes. All types and functions defined by the C library are included in the <code>std</code> namespace, as long as you include the appropriate C++ header (e.g. <code>&lt;cstddef&gt;</code> rather than <code>&lt;stddef.h&gt;</code>)</p> <blockquote> <p>When should I use std::<strong>_</strong>::size_type?</p> </blockquote> <p>Do you mean the <code>size_type</code> types defined in some standard classes and templates such as <code>vector</code>? You could use those when using those classes if you like. In most cases, you'll know that it's the same as <code>size_t</code>, so you might as well use that and save a bit of typing. If you're writing generic code, where you don't know what the class is, then it's better to use <code>size_type</code> in case it's not compatible with <code>size_t</code>.</p> <p>For example, you might want to write a container designed to hold more items than can be represented by <code>size_t</code>. You might use some kind of big number type to represent the container's size, which isn't convertible to <code>size_t</code>. In that case, code like <code>size_t s = c.size()</code> would fail to compile - you'd need to use <code>Container::size_type</code> instead.</p>
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    1. POstd::size_t vs size_t vs std::string::size_type
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    1. COOn your first point, I can use size_t when I haven't included anything. For reference - I'm using VS2010.
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    2. CO@Dave: That's presumably a Microsoft extension to the language - there are a lot of them. Try compiling with language extensions disabled.
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    3. COYou're right about what I meant by `std::____::size_type` but can you elaborate on when it could be 'incompatible' with size_t, and the difference between what std::size_t and ::size_type represent?
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