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PORemoving variable if not filled out
 

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    <p>I'm trying to make a reference generator. People fills in some information, and then the generator sets up the text in the right way. Here's what I've got so far:</p> <pre><code> $('#ref-button1').click(function () { var authorname = $('#bookAuthor').val(); if (authorname == "") { $('.error').show(); return false; } var booktitle = $('#bookTitle').val(); if (booktitle == "") { $('.error').show(); return false; } var year = $('#bookYear').val(); if (year == "") { $('.error').show(); return false; } var place = $('#bookPlace').val(); if (place == "") { $('.error').show(); return false; } var publisher = $('#bookPublisher').val(); if (publisher == "") { $('.error').show(); return false; } var edition = $('#bookEdition').val(); var page = $('#bookPage').val(); var completeString1 = authorname + '&amp;nbsp;' + '(' + year + '),' + '&amp;nbsp;' + '&lt;i&gt;' + booktitle + '&lt;/i&gt;' + ',&amp;nbsp;' + edition + '&amp;nbsp;ed.,&amp;nbsp;' + place + ':&amp;nbsp;' + publisher + ',&amp;nbsp;' + page; $('.error').hide(); $('#output').empty(); $('#output').append(completeString1); }); </code></pre> <p>As you see, I have 5 variables that have to be filled out, and 2 that don't. I create the entire string in completeString1, where I also put in the commas and so on. I know this is probably not the easiest way to do, but it is how I could do it. My problem now, is that my completeString1 will still contain and print "ed.," even if I don't fill out the variable.</p> <p>So my question is: How can I leave out that bit of the variable, given that it is not filled out?</p>
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    1. USViktor
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    1. COWell the code is not optimal as you say, but you do have the `if (variable == "")` part nailed down. So, use the same technique when creating `completeString1`.
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      1. USJon
    2. COand you can group your 'not empty' validation in 1 if statement, with or operator
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      1. USbondythegreat
 

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