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POStatic library & Dynamic library - more C++ fun
 

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    <p>Let's say I want to create a dynamic library <code>dynamic.so</code>, but my code references a function that exists in some other, static library <code>static.a</code>. Naturally, if I compile and link with <code>g++</code> and the <code>-shared</code>option, <code>dynamic.so</code> will expect the referenced function to be implemented in some other dynamic library that I would have to link at runtime together with <code>dynamic.so</code>. In other words, it will be happy as long as I do <code>-l static</code> (modulo syntax).</p> <p>But since that other library is actually a static one, I cannot do that. Let's assume I can not link the static library at compile time of my main program either, but I'm forced to only use dynamic libraries. So what I really want is to include the compiled code off the referenced function from <code>static.a</code> in <code>dynamic.so</code>.</p> <p><a href="https://stackoverflow.com/a/2649792/261142">This answer</a> to a related question suggests using the <code>--whole-archive</code> option to include <code>static.a</code> in <code>dynamic.so</code>. However, in my case, <code>static.a</code> is huge. And I really don't need all of it, I only need that one function definition.</p> <p><a href="https://stackoverflow.com/a/2246926/261142">This answer</a> to another question explains that linking to a static library at compile time means that only the code that is actually referenced gets included in the binary. Well, this is exactly what I would like to do for my single function reference! I don't really want the whole static archive in there.</p> <p>But how can I achieve that? How can I include just the required parts of <code>static.a</code> in <code>dynamic.so</code>? </p>
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