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    <p>Out of sheer curiosity, I integrated my own answer with your original code and F.J.'s solutions to make a comparative performance test.</p> <p>It seems that your solution is the fastest of them all. My solution check all possible elements of the controls tuple, so it will be slower as the size of the tuple increases.</p> <p>Here is the code:</p> <pre><code>from timeit import Timer as T from itertools import chain, dropwhile class control(object): def __init__(self, name): self.name = name def johan_venge(tuple_): for el in tuple_: if el.name == 'foobar': return el return None def mac(tuple_): return filter(lambda x : x.name == 'foobar', tuple_)[0] def mac2(tuple_): return list(dropwhile(lambda x : x.name != 'foobar', tuple_))[0] def fj(tuple_): return next(c for c in tuple_ if c.name == 'foobar') def fj2(tuple_): return next(chain((c for c in tuple_ if c.name == 'foobar'))) if __name__ == '__main__': REPS = 10000 controls = (control('hello'), control('world'), control('foobar')) print T(lambda : johan_venge(controls)).repeat(number = REPS) print T(lambda : mac(controls)).repeat(number = REPS) print T(lambda : mac2(controls)).repeat(number = REPS) print T(lambda : fj(controls)).repeat(number = REPS) print T(lambda : fj2(controls)).repeat(number = REPS) </code></pre> <p>and here is the output on my system:</p> <pre><code>[0.005961179733276367, 0.005975961685180664, 0.005918025970458984] [0.013427019119262695, 0.013586044311523438, 0.013450145721435547] [0.024325847625732422, 0.0254058837890625, 0.02396702766418457] [0.014491081237792969, 0.01442408561706543, 0.01484990119934082] [0.01691603660583496, 0.016616106033325195, 0.016437053680419922] </code></pre> <p>HTH! :)</p>
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    1. POIs there a way to find an item in a tuple without using a for loop in Python?
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    1. COThanks for this test. Btw I am not sure how to interpret the output though :O You have results side by side for the same method but different results for each, line by line?
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    2. CO@JoanVenge - Take a look at the documentation for [`timeit.Timer.repeat`](http://docs.python.org/library/timeit.html#timeit.Timer.repeat). Basically it's three runs of 10.000 iteration each for each solution.
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    3. COThanks mac, now it does make sense. This is probably basic but I noticed you used `'`, but other answers use `"`, any difference for this?
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