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POPython: Concise / elegant way to reformat a set of text files?
primarykey
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8384384
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AcceptedAnswerId
8384741
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4
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4
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CreationDate
2011-12-05T11:08:56.013
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2012-05-01T01:36:19.133
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2012-05-01T01:36:19.133
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text
Body
<p>I have written a python script to process a set of ASCII files within a given dir. I wonder if there is a more concise and/or "pythonesque" way to do it, without loosing readability?</p> <h1>Python Code</h1> <pre><code>import os import fileinput import glob import string indir='./' outdir='./processed/' for filename in glob.glob(indir+'*.asc'): # get a list of input ASCII files to be processed fin=open(indir+filename,'r') # input file fout=open(outdir+filename,'w') # out: processed file lines = iter(fileinput.input([indir+filename])) # iterator over all lines in the input file fout.write(next(lines)) # just copy the first line (the header) to output for line in lines: val=iter(string.split(line,' ')) fout.write('{0:6.2f}'.format(float(val.next()))), # first value in the line has it's own format for x in val: # iterate over the rest of the numbers in the line fout.write('{0:10.6f}'.format(float(val.next()))), # the rest of the values in the line has a different format fout.write('\n') fin.close() fout.close() </code></pre> <h1>An example:</h1> <h2>Input:</h2> <pre><code>;;; This line is the header line -5.0 1.090074154029272 1.0034662411357929 0.87336062116561186 0.78649408279093869 0.65599958665017222 0.4379879132749317 0.26310799350679176 0.087808018565486673 -4.9900000000000002 1.0890770415316042 1.0025480136545413 0.87256100700428996 0.78577373527626004 0.65539842673645277 0.43758616966566649 0.26286647978335914 0.087727357602906453 -4.9800000000000004 1.0880820021223023 1.0016316956763136 0.87176305623792771 0.78505488659611744 0.65479851808106115 0.43718526271594083 0.26262546925502467 0.087646864773454014 -4.9700000000000006 1.0870890372077564 1.0007172884938402 0.87096676998908273 0.78433753775986659 0.65419986152386733 0.4367851929843618 0.26238496225635727 0.087566540188423345 -4.9600000000000009 1.086098148170821 0.99980479337809591 0.87017214936140763 0.78362168975984026 0.65360245789061966 0.4363859610200459 0.26214495911617541 0.087486383957276398 </code></pre> <h2>Processed:</h2> <pre><code>;;; This line is the header line -5.00 1.003466 0.786494 0.437988 0.087808 -4.99 1.002548 0.785774 0.437586 0.087727 -4.98 1.001632 0.785055 0.437185 0.087647 -4.97 1.000717 0.784338 0.436785 0.087567 -4.96 0.999805 0.783622 0.436386 0.087486 </code></pre>
Tags
<python><process><ascii>
Title
Python: Concise / elegant way to reformat a set of text files?
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