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    <p>I suppose you want two things:</p> <p>1) A list of all items</p> <p>2) A list of all items in boxes</p> <p>You can do this in a couple of ways (I'm guessing the structure of your tables here - I'm guessing ItemBox is the link table)</p> <p>a) Select all of the items, then select a list of all of the items in boxes:</p> <pre><code>SELECT I.ItemID, I.Title, B.BoxId, B.Title FROM Item I INNER JOIN ItemBox IB ON (I.ItemID = IB.ItemID) INNER JOIN Box B ON (IB.BoxID = B.BoxID) ORDER BY B.Title, I.Title </code></pre> <p>Should give you all of the items and their boxes.</p> <p>You can then display a list of all items in a form, and a list of box ids (just simple selects from each table).</p> <p>If you cache the results from the above query (in say a dictionary, BoxItem dictionary) then you can look up the item quite simply based on the selected Box.</p> <p>b) you can run the query each time a box is selected:</p> <pre><code>SELECT I.ItemID, I.Title, B.BoxId, B.Title FROM Item I INNER JOIN ItemBox IB ON (I.ItemID = IB.ItemID) INNER JOIN Box B ON (IB.BoxID = B.BoxID) WHERE B.Id = @selected_boxid ORDER BY B.Title, I.Title </code></pre> <p>And update accordingly.</p> <p>Do you need examples for running the query, binding to various controls etc?</p> <p>Here's a version that should do what you want based on your comment:</p> <pre><code>SELECT I.ItemID, I.Title, CASE WHEN IB.ItemID IS NULL THEN 0 ELSE 1 END AS ItemIsInBox FROM Item I LEFT OUTER JOIN ItemBox IB ON (I.ItemID = IB.ItemID); </code></pre>
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    1. POHow to Populate a Checkbox: C# vs T-SQL
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    1. COUltimately, I'd like one result that returns itemID, itemName and a bool column indicating which itemIDs are listed in the lookup table. The lookup table is populated with just itemIDs and boxIDs. the bool column is dependant on @boxID.
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    2. COI've added added a bit more sql at the bottom of the example. If you are familiar with the OUTER JOIN operator then you'll know that this matches all rows in both tables, plus returns null for those rows that don't match. You can use this to see which are in the link table and which aren't
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    3. COThanks for that. I had kinda got that far minus the CASE WHEN. However, this just returns 1 for everything as there is at least one item in each box. But thanks to you I've amended it so: SELECT DISTINCT TOP (100) PERCENT I.itemID, I.Title, CASE WHEN IB.BoxID = @boxID THEN 1 ELSE 0 END AS ItemIsInBox FROM Item AS I LEFT OUTER JOIN ItemBox AS IB ON I.itemID = IB.itemID ORDER BY I.itemID. But it has an issue - see next comment
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