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  1. PO
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    <p>I can not reproduce your problem, this is the EXACT code I'm running (not simplified as the other answers to make it as close as possible to your original question).</p> <pre><code>public class HashProblem { public static class Val { private double x; private double y; public Val(double x, double y) { this.x = x; this.y = y; } @Override public int hashCode() { final int prime = 31; int result = 1; long temp; temp = Double.doubleToLongBits(x); result = prime * result + (int) (temp ^ (temp &gt;&gt;&gt; 32)); temp = Double.doubleToLongBits(y); result = prime * result + (int) (temp ^ (temp &gt;&gt;&gt; 32)); return result; } @Override public boolean equals(Object obj) { if (this == obj) return true; if (obj == null) return false; if (getClass() != obj.getClass()) return false; Val other = (Val) obj; if (Double.doubleToLongBits(x) != Double.doubleToLongBits(other.x)) return false; if (Double.doubleToLongBits(y) != Double.doubleToLongBits(other.y)) return false; return true; } } public static void main(String... args) throws Exception { ArrayList&lt;Double&gt; list; String line; BufferedReader brMyHashval = new BufferedReader(new InputStreamReader(new FileInputStream("HashProblem.txt"))); Hashtable&lt;Val, ArrayList&lt;Double&gt;&gt; numbers = new Hashtable&lt;Val, ArrayList&lt;Double&gt;&gt;(); while ((line = brMyHashval.readLine()) != null) { if (!(line.isEmpty())) { String[] temp; temp = line.split(" "); Double eDouble = Double.parseDouble(temp[2].toString()); Val key = new Val(Double.parseDouble(temp[0].toString()), Double.parseDouble(temp[1].toString())); if (!(numbers.containsKey(key))) { list = new ArrayList&lt;Double&gt;(); numbers.put(key, list); System.err.println("Created " + key.x + " " + key.y); } else { list = numbers.get(key); } list.add(eDouble); System.err.println("Inserted into " + key.x + " " + key.y + " value " + eDouble + " size " + list.size() + " " + list); } } } </code></pre> <p>The output I get from the logging is</p> <pre><code>Created 1.0 2.0 Inserted into 1.0 2.0 value 9.0 size 1 [9.0] Created 3.0 4.0 Inserted into 3.0 4.0 value 9.0 size 1 [9.0] Created 5.0 6.0 Inserted into 5.0 6.0 value 9.0 size 1 [9.0] Inserted into 1.0 2.0 value 8.0 size 2 [9.0, 8.0] Inserted into 5.0 6.0 value 8.0 size 2 [9.0, 8.0] Inserted into 1.0 2.0 value 7.0 size 3 [9.0, 8.0, 7.0] Created 7.0 8.0 Inserted into 7.0 8.0 value 7.0 size 1 [7.0] Inserted into 3.0 4.0 value 7.0 size 2 [9.0, 7.0] Inserted into 5.0 6.0 value 10.0 size 3 [9.0, 8.0, 10.0] Inserted into 1.0 2.0 value 10.0 size 4 [9.0, 8.0, 7.0, 10.0] Created 1.0 3.0 Inserted into 1.0 3.0 value 10.0 size 1 [10.0] Created 1.0 4.0 Inserted into 1.0 4.0 value 10.0 size 1 [10.0] </code></pre> <p>Isn't that what you'd expect?</p> <p>The other answers has good points about simplifying your hashCode and equals. Also, you do not need to do toString() on object that are already strings.</p>
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    1. POJava Hashtable overwrites existing key with new key during 'put'
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    1. USRoger Lindsjö
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      1. VTUpMod
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