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POHow to include the start url in the "allow" rule in SgmlLinkExtractor using a scrapy crawl spider
 

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  1. POHow to include the start url in the "allow" rule in SgmlLinkExtractor using a scrapy crawl spider
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    <p>I have searched a lot of topics but does not seem to find the answer for my specific question. I have created a crawl spider for a website and it works perfectly. I then made a similar one to crawl a similar website but this time I have a small issue. Down to the business:</p> <p>my start url looks as follows: www.example.com . The page contains the links I want to apply my spider look like: </p> <ul> <li>www.example.com/locationA</li> <li>www.example.com/locationB</li> <li>www.example.com/locationC</li> </ul> <p>...</p> <p>I now have a issue: Every time when I enter the start url, it redirects to www.example.com/locationA automatically and all links I got my spider working include </p> <ul> <li>www.example.com/locationB</li> <li>www.example.com/locationC ...</li> </ul> <p>So my problem is how I can include the www.example.com/locationA in the returned URLs.I even got the log info like:</p> <p>-2011-11-28 21:25:33+1300 [example.com] DEBUG: Redirecting (302) to from http://www.example.com/></p> <p>-2011-11-28 21:25:34+1300[example.com] DEBUG: Redirecting (302) to (referer: None)</p> <ul> <li>2011-11-28 21:25:37+1300 [example.com] DEBUG: Redirecting (302) to (referer: www.example.com/locationB)</li> </ul> <p>Print out from parse_item: www.example.com/locationB</p> <p>....</p> <p>I think the issue might be related to that (referer: None) some how. Could anyone please shed some light on this??</p> <p>I have narrow down this issue by changing the start url to www.example.com/locationB. Since all the pages contain the lists of all locations, this time I got my spider works on:</p> <p>-www.example.com/locationA</p> <p>-www.example.com/locationC ...</p> <p>In a nut shell, I am looking for the way to include the url which is same as (or being redirected from) the start url into the list that the parse_item callback will work on.</p>
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    1. COCould you include a short example from your scraper to help us understand your problem in more detail?
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