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    <p>In practice, space for static storage can be allocated as part of the initial binary loading, or by the runtime during startup; but will always happen before user code is encountered.</p> <p>In addition to the constraints that <em>Kerrek SB</em> mentions, the storage for a <code>const expr</code> value could be eliminated if the value itself is never used at runtime.</p> <p>This wouldn't necessarily mean that the value needs to not be evaluated - if a static <code>const expr</code> were only used as a branch condition, that condition may be evaluated statically and other code paths may not be generated or may be excluded by the optimiser.</p> <p>Pretty much any storage with <code>static</code> duration may be eliminated if the implementation can guarantee behaviour as though the storage were present - i.e. a comparison expression that can be evaluated at compile time - like a different <code>const expr</code>, a pointer comparison where the rhs is known to be an alias to a different variable, or perhaps an incompatible type. It may also be eliminated if the value is only read into variables that are never read themselves; or where the value may be reduced to a <code>const expr</code>.</p> <pre><code>struct Foo{}; static Foo bar; // static instance Foo* func() { if ( ! (&amp;bar) ) { // always non-NULL // this block may be eliminated Foo* myCopy(new Foo(bar)); return myCopy; } // so 'bar' is never referred to, and we know it has no side- // effects, so the static variable can be eliminated return new Foo(); } </code></pre> <blockquote> <p><strong>3.7.1 Static storage duration</strong></p> <blockquote> <p><code>2.</code> If an object of static storage duration has initialization or a destructor with side effects, it shall not be eliminated even if it appears to be unused, except that a class object or its copy may be eliminated as specified in 12.8.</p> </blockquote> </blockquote>
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