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    <p>EDIT: I experimented some, and discovered thing are a bit subtler than I thought. Here's what I now think is an accurate answer.</p> <p><code>&amp;s</code> is not an lvalue so you cannot create a reference to it unless the type of the reference is reference to <code>const</code>. So for example, you cannot do</p> <pre><code>string * &amp;r = &amp;s; </code></pre> <p>but you can do</p> <pre><code>string * const &amp;r = &amp;s; </code></pre> <p>If you put a similar declaration in the function header, it will work.</p> <pre><code>void myfunc(string * const &amp;a) { ... } </code></pre> <p>There is another issue, namely, temporaries. The rule is that you can get a reference to a temporary only if it is <code>const</code>. So in this case one might argue that &amp;s is a temporary, and so must be declared <code>const</code> in the function prototype. From a practical point of view it makes no difference in this case. (It's either an rvalue or a temporary. Either way, the same rule applies.) However, strictly speaking, I think it is not a temporary but an rvalue. I wonder if there is a way to distinguish between the two. (Perhaps it is simply defined that all temporaries are rvalues, and all non-lvalues are temporaries. I'm not an expert on the standard.)</p> <p>That being said, your problem is probably at a higher level. Why do you want a reference to the address of <code>s</code>? If you want a reference to a pointer to <code>s</code>, you need to define a pointer as in</p> <pre><code>string *p = &amp;s; myfunc(p); </code></pre> <p>If you want a reference to <code>s</code> or a pointer to <code>s</code>, do the straightforward thing.</p>
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