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    <p>First, yeah, you should probably be using an HTML parser. Here's some sample code using the HTMLParser module that comes with Python:</p> <pre><code>from HTMLParser import HTMLParser class ImgSrcHTMLParser(HTMLParser): def __init__(self): HTMLParser.__init__(self) self.srcs = [] def handle_starttag(self, tag, attrs): if tag == 'img': self.srcs.append(dict(attrs).get('src')) parser = ImgSrcHTMLParser() parser.feed(html) for src in parser.srcs: print src </code></pre> <p>This collects the src from img tags. It should be pretty easy to adapt it to your purposes assuming you want the href of 'a' tags that end in '.mp3'.</p> <p>Assuming you really want to use a regex, there are some issues with your regex. You aren't delimiting the URL and you're using dot inside the URL. The worst side-effect of this is that a non-mp3 URL followed by an mp3-URL will be treated as one long URL. eg: "<a href="http://foo/bar.gif" rel="nofollow noreferrer">http://foo/bar.gif</a> snarf snarf <a href="http://baz/quux.mp3" rel="nofollow noreferrer">http://baz/quux.mp3</a>". You probably want to require some kind of delimiter (spaces, quotes, depends on what you're doing) and disallow some characters inside URLs (probably the same characters and/or any characters that aren't allowed in URLs). Also, you forgot to escape the "." in ".mp3". So "<a href="http://foo/mp3icon.gif" rel="nofollow noreferrer">http://foo/mp3icon.gif</a>" will match as "<a href="http://foo/mp3" rel="nofollow noreferrer">http://foo/mp3</a>".</p>
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    1. POI need a regex for the href attribute for an mp3 file url in python
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    1. USLaurence Gonsalves
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    1. COThanks Laurence. This clears up a few things. I will give regular expressions a couple more tries (simply to learn how to properly use them) before going the parser route. But, you described the problem quite accurately: a non-mp3 URL followed by an mp3 URL will be treated as one long URL.
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