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POHQL/SQL/Criteria to join-match all records in a given list while selecting all fields
 

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    <p>I'm trying to write a HQL/Criteria/Native SQL query that will return all Employees that are assigned to a list of Projects. They must be assigned to <em>all</em> Projects in order to be selected.</p> <p>An acceptable way of achieving this with native SQL can be found in the answer to this question: <a href="https://stackoverflow.com/q/1849535/851811">T-SQL - How to write query to get records that match ALL records in a many to many join</a>: </p> <pre><code>SELECT e.id FROM employee e INNER JOIN proj_assignment a ON e.id = a.emp_id and a.proj_id IN ([list of project ids]) GROUP BY e.id HAVING COUNT(*) = [size of list of project ids] </code></pre> <p>However, I want to select all fields of Employee (<code>e.*</code>). It's not possible to define <a href="https://stackoverflow.com/q/800910/851811">SQL grouping by all the columns</a>(<code>GROUP BY e.*</code>), <code>DISTINCT</code> should be used instead. Is there a way to use <code>DISTINCT</code> altogether with <code>COUNT(*)</code> to achieve what I want?</p> <p>I've also tried using HQL to perform this query. The <code>Employee</code> and <code>ProjectAssignment</code> classes don't have an association, so it's not possible to use Criteria to join them. I use a cross join because it's the way to perform a <a href="https://stackoverflow.com/q/974085/851811">Join without association in HQL</a>. So, my HQL looks like</p> <pre><code>select emp from Employee emp, ProjectAssignment pa where emp.id = pa.empId and pa.paId IN :list group by emp having count(*) = :listSize </code></pre> <p>However, due to a bug in Hibernate, <a href="https://hibernate.onjira.com/browse/HHH-1615" rel="nofollow noreferrer">GROUP BY entity does not work</a>. The SQL it outputs is something like <code>group by (emptable.id)</code>.</p> <p>Subquerying the assignment table for each project (dynamically adding <code>and exists (select 1 from proj_assignment pa where pa.emp_id=e.id and pa.proj_id = [anId])</code> for each project in the list) is not an acceptable option.</p> <p>Is there a way to write this query properly, preferrably in HQL (in the end I want a <code>List&lt;Employee&gt;</code>), without modifying mappings and without explicitly selecting all columns in the native SQL ?</p> <hr> <p><strong>EDIT</strong>: I'm using Oracle 10g and <a href="http://repo1.maven.org/maven2/org/hibernate/hibernate-annotations/3.3.1.GA/hibernate-annotations-3.3.1.GA.pom" rel="nofollow noreferrer">hibernate-annotations-3.3.1.GA</a></p>
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