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  1. POText to XML in python
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    <p>I'm trying to convert text into <code>xml</code> format. And I'm using <code>LXML</code> Library. But I'm getting error message. Please help me. Thank you </p> <pre><code>import re from lxml import etree import urllib,urllib2 def get_movie_info(movie_id): URL = "http://www.raaga.com/a/rss.asp?%s"%(movie_id) f = urllib.urlopen(URL) movie_info = f.read() rss = "".join([ line.strip() for line in movie_info ]) mi_tree = etree.fromstring(rss) #mi_title = self._parse_movie_title(mi_tree.xpath("/rss/channel/title/text()")[0]) #mi_tracks = mi_tree.xpath("/rss/channel/item") return mi_tree get_movie_info('A0000102') </code></pre> <p>Here is my traceback</p> <pre><code> Traceback (most recent call last): File "py1.py", line 14, in &lt;module&gt; get_movie_info('A0000102') File "py1.py", line 9, in get_movie_info mi_tree = etree.fromstring(rss) File "lxml.etree.pyx", line 2743, in lxml.etree.fromstring (src/lxml\lxml.etre e.c:52665) File "parser.pxi", line 1573, in lxml.etree._parseMemoryDocument (src/lxml\lxm l.etree.c:79932) File "parser.pxi", line 1452, in lxml.etree._parseDoc (src/lxml\lxml.etree.c:7 8774) File "parser.pxi", line 960, in lxml.etree._BaseParser._parseDoc (src/lxml\lxm l.etree.c:75389) File "parser.pxi", line 564, in lxml.etree._ParserContext._handleParseResultDo c (src/lxml\lxml.etree.c:71739) File "parser.pxi", line 645, in lxml.etree._handleParseResult (src/lxml\lxml.e tree.c:72614) File "parser.pxi", line 585, in lxml.etree._raiseParseError (src/lxml\lxml.etr ee.c:71955) lxml.etree.XMLSyntaxError: xmlParsePITarget: invalid name prefix 'xml', line 1, column 13 </code></pre>
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