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POWhy can't I put my function inside jQuery(document).ready(function() { }
 

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  1. POWhy can't I put my function inside jQuery(document).ready(function() { }
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    <p>Why can't I put the function below inside <code>jQuery(document).ready(function() { }</code> ?</p> <pre><code> function csf_map_maker_js( args ) {   // Default js args.  Args passed to function will override these.   var default_args = { width : 610, height : 400,     latitude :  37.93,     longitude :  -75.09,     zoom : 8, mtype: 'ROADMAP', encoded_points: ' blah blah', id: 'csf_map_canvas', hood: 'My Neighborhood'   };   for ( var index in default_args ) {     if ( typeof args[index] == "undefined" ) {       args[index] = default_args[index];     }   }  var latlng = new google.maps.LatLng(args['latitude'], args['longitude']); var encodedPoints = args['encoded_points']; var decodedPoints = google.maps.geometry.encoding.decodePath(encodedPoints);  var myOptions = {     zoom: parseInt( args['zoom'] ),     center: latlng,     mapTypeId: google.maps.MapTypeId[args['mtype']], streetViewControl: true, zoomControl: true, panControl: true   }; csf_map = new google.maps.Map(document.getElementById( args['csf_id'] ), myOptions); var encodedPolygon = new google.maps.Polyline ({ strokeColor: "#0000FF", strokeOpacity: 0.55, strokeWeight: 5, path: decodedPoints, fillOpacity: 0, clickable: false, map: csf_map }); } </code></pre> <p>If I put it outside, the (document).ready block it works, (although I think that some other functions are getting called before the map loads). The code is for a WordPress plugin.</p> <p>The function gets called in the php script as follows:</p> <pre><code>$csf_map_output .= '&lt;div id="csf_map_canvas" style="width:'. $atts['width'].'px; height: '. $atts['height'] .'px;"&gt;&lt;/div&gt;'; $csf_map_output .= '&lt;script&gt;var csf_map_params = ' . json_encode( $atts ) . '; csf_map_maker_js( csf_map_params );&lt;/script&gt;'; return $csf_map_output; </code></pre> <p>Do I need to change the way the function is called in the php script when it's inside <code>jQuery(document).ready(function() { }</code> ? </p>
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    1. COThis code seems to be missing an ending `}` -- is that your problem?
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    2. COtry $(document).ready(function() {});
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    3. COThank you for the message. I've got the ending ); in my code, but I didn't include it in my question. The $ is the same as writing jQuery.
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