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2011-11-14T20:53:14.617
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<p>The way I did it is to identify the methods that I needed from the original Path class and then simply override those methods as follows:</p> <pre><code>public class CustomPath extends Path implements Serializable { private static final long serialVersionUID = -5974912367682897467L; private ArrayList<PathAction> actions = new ArrayList<CustomPath.PathAction>(); private void readObject(ObjectInputStream in) throws IOException, ClassNotFoundException{ in.defaultReadObject(); drawThisPath(); } @Override public void moveTo(float x, float y) { actions.add(new ActionMove(x, y)); super.moveTo(x, y); } @Override public void lineTo(float x, float y){ actions.add(new ActionLine(x, y)); super.lineTo(x, y); } private void drawThisPath(){ for(PathAction p : actions){ if(p.getType().equals(PathActionType.MOVE_TO)){ super.moveTo(p.getX(), p.getY()); } else if(p.getType().equals(PathActionType.LINE_TO)){ super.lineTo(p.getX(), p.getY()); } } } public interface PathAction { public enum PathActionType {LINE_TO,MOVE_TO}; public PathActionType getType(); public float getX(); public float getY(); } public class ActionMove implements PathAction, Serializable{ private static final long serialVersionUID = -7198142191254133295L; private float x,y; public ActionMove(float x, float y){ this.x = x; this.y = y; } @Override public PathActionType getType() { return PathActionType.MOVE_TO; } @Override public float getX() { return x; } @Override public float getY() { return y; } } public class ActionLine implements PathAction, Serializable{ private static final long serialVersionUID = 8307137961494172589L; private float x,y; public ActionLine(float x, float y){ this.x = x; this.y = y; } @Override public PathActionType getType() { return PathActionType.LINE_TO; } @Override public float getX() { return x; } @Override public float getY() { return y; } } } </code></pre> <p>In my example I need "moveTo" and "lineTo", so in this case I simply hold the drawing information in a list. This list contains the drawing information (what I call "action") needed by Path in order to restore the drawing as it looked like before the object was serialized. Then when I deserialize my objects of type CustomPath i make sure to let <a href="http://java.sun.com/developer/technicalArticles/Programming/serialization/">the default serialization protocol</a> call "drawThisPath", so the path is redrawn.</p>
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1. POhow to serialize an object of android.graphics.Path
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1. USRabie Jradi
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