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  1. POConfusion with a while statement evaluating if a number is triangular
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    <p>I've been having troubles trying to figure out how to solve a function. I've been assigned the development of a little programme which tells if a number is "triangular" (a number is triangular when the addition of certain consecutive numbers in the [1,n] interval is n. Following the definition, the number 10 is triangular, because in the [1,10] interval, 1+2+3+4=10).</p> <p>I've coded this so far:</p> <pre><code>class TriangularNumber{ boolean numTriangular(int n) { boolean triangular = false; int i = n; while(n&gt;=0 &amp;&amp; triangular){ //UE06 is a class which contains the function "f0", which makes the addition of all the numbers in a determined interval UE06 p = new UE06(); if ((p.f0(1, i))==n) triangular = true; else i=i-1; } return triangular; } boolean testTriangular = numTriangular(10) == true &amp;&amp; numTriangular(7) == false &amp;&amp; numTriangular(6) == true; public static void main(String[] args){ TriangularNumber p = new TriangularNumber(); System.out.println("testTriangular = " + p.testTriangular); } } </code></pre> <p>According to those boolean tests I made, the function is wrong. As I see the function, it goes like this: </p> <ol> <li>I state that the input number in the initial state isn't triangular (triangular=false) and i=n (determining the interval [1,i] where the function is going to be evaluated</li> <li>While n is greater or equals 0 and the number isn't triangular, the loop starts</li> <li>The loop goes like this: if the addition of all the numbers in the [1,i] interval is n, the number is triangular, causing the loop to end. If that statement is false, i goes from i to (i-1), starting the loop again with that particular interval, and so on till the addition is n.</li> </ol> <p>I can't spot the error in my "algorithm", any advice?</p> <p>Thanks!</p>
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